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3 years ago

Question 3

Mathematics

2 answers:

djyliett [7]3 years ago

5 0

Answer:This is so confusing

Step-by-step explanation:

Damm [24]3 years ago

3 0

Answer:

C its 16

Step-by-step explanation:

i would not give the wrong answer

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Evaluate 4 M-n if m= -7 and n = 5.

Svetradugi [14.3K]

Answer: -12

Step-by-step explanation: because -7- 5= -12

4 0

3 years ago

Sally made a box to hold her jewlery collection. She used 42 inches of wood to build the sides of the box. If the box is 9 inche

Juliette [100K]

The length is 12, because if it's 9 inches wide it has two sides of 9 inches which is 18. Then subtract that from the intial value 42 to get 24. After, you divide 24 by 2 due to there being 2 sides of the box and 24 is the sum of both sides. Hopethis helps!

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3 years ago

Which number rounds to 15,700,000 when rounded to the nearest hundred thousand?. A) 15,000,000. B) 15,579,999. C) 15,649,999. D)

Artyom0805 [142]

The correct answer is option D. i.e. 15,659,999. Now, this number is closest to the given number i.e. 15,700,000. Becuase when 659 is rounded to the nearest number of hiher value then its value will be 700. Thus,15,659, 999 rounds to 15,700,000 when rounded to the nearest hundred thousand.

6 0

3 years ago

Fracciones equivalente 1/4

stealth61 [152]

2/4 esa es una ojalá y pude contestar a tiempo

6 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago