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3 years ago

(WILL GIVE BRAINLYIST IF ANSWER IS RIGHT!)

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

6 0

Answer:

The answer is 1 and 4

Step-by-step explanation:

.25 x 4y = Y

36 divided by 4 = 9

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What is the sum _71/6 +35/6 in the simplest terms ? Show your work

adoni [48]

Answer:

The answer in simplest term is 35.33333334.

Step-by-step explanation:

First, we need to divide 71 and 6.

71/6 = 23.66666667.

Now we need to divide 35 and 6.

35/6 = 11.66666667.

Now we need to add the two quotients.

23.66666667 + 11.66666667 = 35.33333334.

And that is the final answer.

I hope this helps!

7 0

3 years ago

What is the answer to 1-2x=-3x+2

scZoUnD [109]

Answer:

x=1

Step-by-step explanation:

1-2x=-3x+2

-1=-x

1=x

8 0

3 years ago

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What is an equation of the line that passes through the point (-6, -7) and is

Alexandra [31]

Answer:

Step-by-step explanation:

Product of slope of perpendicular lines = -1

6x + 5y = 30

Write this equation in y = mx + b form

5y = -6x + 30

y = $\frac{-6}{5}x+\frac{30}{5}$

$y=\frac{-6}{5}x + 6$

Slope of this line m₁ = -6/5

m₁ * m₂ = -1

m₂ = -1÷m₁ = -1 * $\frac{5}{-6}$

$m_{2}=\frac{5}{6}$ & (-6 , -7)

Equation of the required line: y - y₁ = m (x - x₁)

$y - (-7) = \frac{5}{6}(x - [-6])\\\\y + 7 = \frac{5}{6}x + 6 *\frac{5}{6}\\\\y = \frac{5}{6}x +5-7\\\\y=\frac{5}{6}x-2$

8 0

3 years ago

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

3 0

3 years ago

What is the slope of the line that<br> asses through these two points?<br> (1, -2)<br> (3, 4)

dusya [7]

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{(-2)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{1}}}\implies \cfrac{4+2}{2}\implies \cfrac{6}{2}\implies 3$

3 0

3 years ago

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