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slava [35]
1 year ago
10

How many solutions does the equation 6n − 6n − 12 = 14 − 2 have? two one none infinite

Mathematics
1 answer:
tekilochka [14]1 year ago
7 0

Answer:

no solutions

Step-by-step explanation:

6n - 6n - 12 = 14 - 2 = 12 ( add 12 to both sides )

0 = 24 ← not possible

this indicates the equation has no solution

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(x+y=31)2
2x-y=11
2x+2y=62
- 2x -y=11
3y=51
y=17
x+17=31
x=14
y-x=3
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3 years ago
Help out dudes!! #38.
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You earn $15 per lawn. 1 lawn would be $15. 15(1) is 15.
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Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.
LuckyWell [14K]

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle.

Opposite angles of a Quadrilateral are Supplementary.

\therefore \: \angle A + \angle C = 180° \\  \therefore \:(2x + 3) \degree+ (2x + 1) \degree = 180° \\  \therefore \: (4x + 4) \degree = 180° \\ \therefore \: (4x + 4) = 180 \\ \therefore \: 4x = 180 - 4 \\ \therefore \: 4x = 176 \\ \therefore \: x =  \frac{176}{4}  \\ \therefore \: x =  44 \\  \\  m\angle A  = (2x + 3) \degree \\  = (2 \times 44 + 3) \degree \\ = (88 + 3) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle A  =91 \degree}} \\  \\ m\angle  C = (2x + 1) \degree \\  = (2 \times 44 + 1) \degree \\ = (88 + 1) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle   C=89\degree}}  \\  \\ m\angle  D= (x - 10) \degree \\  = (44 - 10) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle  D =34\degree}}  \\  \\ similarly \\  \\  \huge \red{ \boxed{ \therefore \: m\angle  B  = 146\degree}}   \\  \\

6 0
3 years ago
Please help? It's worth 16 points!!!!
ddd [48]

Answer:

I’m not too sure what your question is exactly but if your just trying to graph the two equations I can help u with that (:

Step-by-step explanation:

The first thing you should do is change the second equation to slope intercept form. It is much easier for most people. From there write out your table by choosing a number for x then plugging that number into the equation to find y. For the first equation (y=1/3x+2) it’s always easier to use multiple of three for the number of x. For example, if 3 was my number for x I would multiply 1/3 by 3=1 then simply add 2=3. So the coordinates for one point on that table would be 3,3. You continue to do that for each graph then plot your points. (In my graph, purple is the equation y+9=-9/3x-9 and black equals the equation y=1/3x+2

4 0
3 years ago
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In each of the following equations, what is
timama [110]

The graph will cross at the coordinates (-2, 9)

<h3>How to solve equations?</h3>

y = 3x + 15

y = 3 - 3x

y = 3x + 15

Hence,

when x = 2

y = 3(2) + 15 = 21

when x = 0

y = 3(0) + 15 = 15

y = 3 - 3x

when x = 2

y = 3 - 3(2)

y = 3 - 6

y = -3

when x = 0

y = 3 - 3(0)

y = 3

Therefore, let's check if the equation will cross.

y = 3x + 15

y = 3 - 3x

using substitution,

3 - 3x = 3x + 15

3  - 15 = 3x + 3x

- 12 = 6x

x = -12 / 6

x = -2

y = 3 - 3(-2)

y = 3 + 6

y = 9

Therefore, the graph will cross at the coordinates (-2, 9)

learn more on equations here: brainly.com/question/19297665

#SPJ1

8 0
2 years ago
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