Answer:
e. ![1.8\times 10^{-6}m^3](https://tex.z-dn.net/?f=1.8%5Ctimes%2010%5E%7B-6%7Dm%5E3)
Step-by-step explanation:
It is given that,
The density of intergalactic space material is
kg per cubic meter.
And the volume of intergalactic space material is ![8.0\times 10^{24} m^3](https://tex.z-dn.net/?f=8.0%5Ctimes%2010%5E%7B24%7D%20m%5E3)
So the mass of that much intergalactic space material is,
, where 'm' is the mass, and 'v' is the volume.
Putting the values we get,
![m=2.5 \times 10^{-27}\times 8.0 \times 10^{24}](https://tex.z-dn.net/?f=m%3D2.5%20%5Ctimes%2010%5E%7B-27%7D%5Ctimes%208.0%20%5Ctimes%2010%5E%7B24%7D)
![m=20\times 10^{(-27+24)}=20\times 10^{-3} kg](https://tex.z-dn.net/?f=m%3D20%5Ctimes%2010%5E%7B%28-27%2B24%29%7D%3D20%5Ctimes%2010%5E%7B-3%7D%20kg)
It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is ![20 \times 10^{-3}=2 \times 10^{-2}kg](https://tex.z-dn.net/?f=20%20%5Ctimes%2010%5E%7B-3%7D%3D2%20%5Ctimes%2010%5E%7B-2%7Dkg)
So the volume of lead is,
![v=\frac{m}{\rho} =\frac{2 \times 10^{-2}}{11300} = 0.00000177 m^3](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bm%7D%7B%5Crho%7D%20%3D%5Cfrac%7B2%20%5Ctimes%2010%5E%7B-2%7D%7D%7B11300%7D%20%3D%200.00000177%20m%5E3)
![v=1.77 \times 10^{-6}=1.8\times 10^{-6}m^3](https://tex.z-dn.net/?f=v%3D1.77%20%5Ctimes%2010%5E%7B-6%7D%3D1.8%5Ctimes%2010%5E%7B-6%7Dm%5E3)
So the volume of lead is
.
Answer:
-4a/-8 +-12a
Step-by-step explanation:
I'm assuming its just asking you to put it down and now solve it so, I plugged in the top to the bottom, and multiplied it all; getting ^, if its asking for a more simplified answer it would be a/2 + 12a ... I think
The greatest common factor of 10 is 10 and the least common factor of 15 is 15
Hope I helped!!!!!
Answer:
16 in × 20 in
Step-by-step explanation:
- Finding the % of the picture that can fit in 16×20 frame
Area of picture= length by width
=4*6=24 in²
Area of frame=Length by width
=16*20=320 in²
% of the picture in the frame will be
(24/320) * 100% =7.5%
2. Finding the % of the picture that can fit in 18 × 24 frame
Area of picture=24 in²
Area of frame =Length by width
=18*24=432 in²
% of the picture in the frame will be;
(24/432)*100%=5.6%
The frame 16 by 20 in will keep 7.5% of the original picture
The frame 18 by 24 in will keep 5.6% of the original picture
Hence you should use the frame of 16 by 20 in because it will keep more of the original picture.