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Iteru [2.4K]
3 years ago
6

Which property was used to simplify the expression?I will mark brainliest for the correct answer.

Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0
Commutative property.
Sense nothing really changed and they just moved.
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Jack can text 180 words in 2 minutes and 45 seconds. What is his unit rate in texts per second?
grigory [225]

Answer: 1.091 which is approximately 1 word per second

Step-by-step explanation:

Jack can text 180 words in 2 minutes and 45 seconds. We would convert 2 minutes to seconds

60 seconds = 1 minute

x seconds = 2 minutes

x = 2×60 = 120 seconds

2 minutes 45seconds = 120+45 = 165 seconds

This means Jack can text 180 words in 165 seconds

Let's find his unit rate in texts per second

if jack texts 180 words in 165 seconds

Then jack texts y words in 1 second

165y = 180

y = 180/165= 1.091 words per second

This is approximately 1 word per second

7 0
2 years ago
11. The student council is comparing prices for their semi-formal dance. They compare banquet. Hall A charges $40 per person. Ha
Natalka [10]

Answer:

TC (A) = 40x , TC (B) = 500 + 20x

Step-by-step explanation:

Let the number of students be = x

Hall A Total Cost

Relationship Equation, where TC (A) = f (students) = f (x)                                40 per person (student) = 40x

Hall B Total Cost

Relationship Equation, where TC (B) = f (students) = f (x)                          500 fix fee & 20 per person (student) = 500 + 20x

4 0
2 years ago
A second bag of 40 marbles contains 11 red marbles, 9 blue marbles and 20 green marbles.
Goryan [66]

Answer:

Where is the first bag? We cant solve the question without knowing the marbles in the first bag

8 0
3 years ago
Read 2 more answers
The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both increased by 2
ivolga24 [154]

Question:

The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both decreased by 2, the fraction is now equal to  \frac{1}{2}.

If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?

5n = 3d and n - 2 = 2d - 4

5n = 3d and 2n - 4 = d - 2

3n = 5d and 2n - 4 = d - 2

Answer:

5n = 3d and 2n – 4 = d – 2

Solution:

Let n be the numerator of the fraction and d be the denominator of the fraction.

Given the numerator and denominator of a fraction are in the ratio of 3 to 5.

This can be written as n : d = 3 : 5.

⇒ \frac{n}{d}= \frac{3}{5} – – – – (1)

Do cross multiplication, we get

⇒ 5n = 3d

When the numerator and denominator are decreased by 2, the fraction is equal to \frac{1}{2}.

⇒ \frac{n-2}{d-2}= \frac{1}{2}

Do cross multiplication, we get

⇒ 2(n –2)=1(d – 2)

⇒ 2n – 4 = d – 2

Hence, 5n = 3d and 2n – 4 = d – 2 can be used to solve the problem.

6 0
3 years ago
Read 2 more answers
Find the area of the shaded region.
MariettaO [177]

Answer:

Area of  shaded region = 134.13 square feet

Step-by-step explanation:

Area of the shaded region = Area of square - Area of circle

                                         = ( 25 \times 25) - ( \pi 12.5^2)\\= 625 - 490.87\\= 134.13 ft^2

8 0
2 years ago
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