Question

The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballgame (event B) the same day is 0.61. The probability that Kate and Jane both go to the ballgame on Monday is 0.52.
From the given scenario, we can conclude that events A and B are

Answer 1

Answer:

dependent events since P(A and B) is not equal to P(A) * P(B)

Step-by-step explanation:

According to the Question,

• Given, The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballgame (event B) the same day is 0.61. The probability that Kate and Jane both go to the ballgame on Monday is 0.52.

Thus, The events A, B and A∩B are:

A - Jane will go to a ballgame on Monday;

B - Kate will go to a ballgame on Monday;

A∩B - Kate and Jane both go to the ballgame on Monday.

• P(A)=0.73, P(B)=0.61, P(A∩B)=0.52.

• Pr(A)⋅Pr(B) = 0.73⋅0.61 = 0.4453 ≠ 0.52

So, events A and B are dependent events since P(A and B) is not equal to P(A) * P(B)