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Over [174]
3 years ago
5

Simplify each expression 4a + 5a^2 + 2a^2 + a^2

Mathematics
2 answers:
shtirl [24]3 years ago
6 0

Answer:

<h2>4a + 8a^2</h2>

Step-by-step explanation:

<h3>4a + 5a^2 + 2a^2 + a^2</h3><h3>= 4a + 8 a^2</h3>

<h3>good \: luck</h3>
Natasha_Volkova [10]3 years ago
3 0

Answer:

a(4+5a+2a+a) or

a(5a+2a+a+4)

Step-by-step explanation:

You could take out one A from each number since they all have an A in them. You could reorganize it and put it in numerical order. Hope this helped :)

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4 Points
Vladimir [108]

Answer:

35

Step-by-step explanation:

One is given the following function (y=3x+5). The given problem asks one to find the output of the function when the input is (10). Keep in mind, a general rule for dealing with functions is that, when present, the variable (x) represents the input. Whereas the variable (y) represents the output. Thus, if one were to substitute (10) in place of (x), and simplify: the result one would get is the output. Apply this idea to the given scenario:

y=3x+5

y=3(10)+5

y=30+5

y=35

4 0
3 years ago
What is another way to write 54?
never [62]

Answer:

None of the above.

5 0
3 years ago
Read 2 more answers
If 4 apples cost 0.80, how much do 12 apples cost
Neporo4naja [7]
4 / 0.80 = 12 / x...cross multiply
4x = 0.80 * 12
4x = 9.6
x = 9.6 / 4
x = 2.4.....12 apples cost $ 2.40
3 0
3 years ago
Read 2 more answers
-3+m/3=12 how do I solve this
timama [110]
First: You add 3 to each side. Second: You multiply each side by 3. Third: You gaze in wondrous amazement at the answer, which lies revealed before you on the page.
3 0
3 years ago
Read 2 more answers
Give an example of this when adding two rationalnumbers with different signs and provide the product.
kolezko [41]

ANSWER:

\begin{gathered} \frac{4}{5}+-\frac{8}{3}=-\frac{28}{15} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{32}{15} \end{gathered}

STEP-BY-STEP EXPLANATION:

Rational numbers are all numbers that can be expressed as a fraction, that is, as the quotient of two whole numbers.

Therefore, an example would be:

\begin{gathered} \frac{4}{5}\text{ and - }\frac{8}{3} \\ \text{adding} \\ \frac{4}{5}+-\frac{8}{3}=\frac{4}{5}-\frac{8}{3} \\ \frac{4}{5}-\frac{8}{3}=\frac{4\cdot3-5\cdot8}{5\cdot3}=\frac{12-40}{15}=-\frac{28}{15} \\ \text{ product} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{4\cdot8}{5\cdot3}=-\frac{32}{15} \end{gathered}

5 0
1 year ago
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