What is the answer to this???

g A restaurant offers 7 entrees and 11 desserts. In how many ways can a person order a two-course meal?

Kitty [74]

Answer:

$2-course\ meal = 77\ ways$

Step-by-step explanation:

Given

$Entrees = 7$

$Desserts = 11$

Required

Determine the number of ways to get a two-course meal

This is solved as follows:

The entrees can be ordered in 7 ways

The desserts can be ordered in 11 ways;

$2-course\ meal = Entrees * Desserts$

Hence:

$2-course\ meal = 7 * 11$

$2-course\ meal = 77\ ways$

8 0

3 years ago

Aurora is planning to participate in an event at her school's field day that requires her to complete tasks at various stations

Ipatiy [6.2K]

Answer:

a) geometric

Step-by-step explanation:

a) geometric

An arithmetic sequence is an ordered set of numbers that have a common difference between each consecutive term, but it is not like this, so it is a geometric sequence.

7 0

3 years ago

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A recent study focused on the number of times men and women who live alone buy take-out dinner in a month. Assume that the distr

Marianna [84]

Answer:

(a) Decision rule for 0.01 significance level is that we will reject our null hypothesis if the test statistics does not lie between t = -2.651 and t = 2.651.

(b) The value of t test statistics is 1.890.

(c) We conclude that there is no difference in the mean number of times men and women order take-out dinners in a month.

(d) P-value of the test statistics is 0.0662.

Step-by-step explanation:

We are given that a recent study focused on the number of times men and women who live alone buy take-out dinner in a month.

Also, following information is given below;

Statistic : Men Women

The sample mean : 24.51 22.69

Sample standard deviation : 4.48 3.86

Sample size : 35 40

Let $\mu_1$ = mean number of times men order take-out dinners in a month.

$\mu_2$ = mean number of times women order take-out dinners in a month

(a) So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in the mean number of times men and women order take-out dinners in a month}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2\neq$ 0 {means that there is difference in the mean number of times men and women order take-out dinners in a month}

The test statistics that would be used here Two-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_-_n_2_-_2$

where, $\bar X_1$ = sample mean for men = 24.51

$\bar X_2$ = sample mean for women = 22.69

$s_1$ = sample standard deviation for men = 4.48

$s_2$ = sample standard deviation for women = 3.86

$n_1$ = sample of men = 35

$n_2$ = sample of women = 40

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(35-1)\times 4.48^{2}+(40-1)\times 3.86^{2} }{35+40-2} }$ = 4.16

So, test statistics = $\frac{(24.51-22.69)-(0)}{4.16 \sqrt{\frac{1}{35}+\frac{1}{40} } }$ ~ $t_7_3$

= 1.890

(b) The value of t test statistics is 1.890.

(c) Now, at 0.01 significance level the t table gives critical values of -2.651 and 2.651 at 73 degree of freedom for two-tailed test.

Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that there is no difference in the mean number of times men and women order take-out dinners in a month.

(d) Now, the P-value of the test statistics is given by;

P-value = P( $t_7_3$ > 1.89) = 0.0331

So, P-value for two tailed test is = 2 $\times$ 0.0331 = 0.0662

4 0

3 years ago

The table below displays the purchases that Graphic DesignWorks made from

AveGali [126]

If Graphic Design Works uses LIFO and has 125 shorts left in its inventory, the value of its current stock is D. $1485.

<h3>What is the LIFO inventory system?</h3>

The Last-In, First-Out (LIFO) method is an inventory valuation method that assumes that the last units to arrive in inventory are sold first.

The LIFO method is allowed under US GAAP. It is the opposite of FIFO (First-in, First-Out). The FIFO method assumes that the units bought first are the first to be sold.

<h3>Data and Calculations:</h3>

Month of Number Price per Total Cost

Purchase of shorts shorts

June 40 $11 440 (40 x $11)

July 60 $12 720 (60 x $12)

August 80 $13 1,040 (80 x $13)

September 90 $14 1,260 (90 x $14)

Ending inventory 125

Using LIFO:

Value of ending inventory = $1,485 ($440 + $720 + $13 x 25)

Thus, if Graphic Design Works uses LIFO and has 125 shorts left in its inventory, the value of its current stock is D. $1485.

Learn more about the LIFO inventory method at brainly.com/question/6640325

#SPJ1

6 0

2 years ago

Marjorie bought a new car with some miles already clocked on it. She kept track of the miles she put on her new car each day, as

Citrus2011 [14]

Answer:

the answer is 150

Step-by-step explanation:

4 0

3 years ago

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