Answer:
(7,4)
Step-by-step explanation:
Answer:
<em>-9.5 + 6x ≥ 42.1 </em>
<em>6x ≥ 51.6</em>
x ≥ 8.6
Here, we can see that x is greater than or equal to 8.6. So, we can say that 8.6 is the lowest value of x
but we have 2 options with 8.6 as the lowest term, we can see that the brackets are different in the beginning
the '[' bracket tells us to include 8.6 in the values of x whereas the '(' bracket tells to exclude 8.6 from the possible values of x
since we know that x is greater than or equal to 8.6, we will use the '[' bracket
Hence, b is your answer
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SOLUTION
The mean is 4min
standard deviation is 1min
the z score is
where
then we have
The probability the call lasted less than 3 min will be
Therefore, the probability that (z < -1 ) is
[tex]\begin{gathered} Pr(z<-1)=Pr(0
Hence, the percentage of the calls that lasted less than 3 min is 16%
