2 years ago

Write. (8×100,000)+(4×1,000)+(6×1) in to other

Mathematics

1 answer:

Scorpion4ik [409]2 years ago

3 0

(8x100,000)+(4x1,000)+(6x1)

=800,000+4,000+6

=804,006

So an answer is 804,006. I think that my answer will help you!

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9, 2, -5... so is going down by 7 each time, meaning the "common difference" is -7.

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=9\\
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a_n=-187
\end{cases}
\\\\\\
-187=9+(n-1)(-7)\implies -187=9-7n+7
\\\\\\
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