6-6.
6^-8/6^-2 becomes 6^-8(6^2) which is 6^-8+2=6^-6
QUESTION 3
The sum of the interior angles of a kite is .
.
.
.
.
But the two remaining opposite angles of the kite are congruent.
.
.
.
.
QUESTION 4
RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.
Using the Pythagoras Theorem, we obtain;
QUESTION 5
The given figure is an isosceles trapezium.
The base angles of an isosceles trapezium are equal.
Therefore
QUESTION 6
The measure of angle Y and Z are supplementary angles.
The two angles form a pair of co-interior angles of the trapezium.
This implies that;
QUESTION 7
The sum of the interior angles of a kite is .
.
.
.
.
But the two remaining opposite angles are congruent.
.
.
.
.
QUESTION 8
The diagonals of the kite meet at right angles.
The length of BC can also be found using Pythagoras Theorem;
QUESTION 9.
The sum of the interior angles of a trapezium is .
.
.
But the measure of angle M and K are congruent.
.
.
.
.
9514 1404 393
Answer:
14.01, 493, 87
Step-by-step explanation:
Subtracting 28 from both sides tells you the range of values you need to be looking at.
28 + x > 42
x > 14
Any values more than 14 will make the inequality true. Three of them are ...
14.01, 493, 87