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leva [86]
3 years ago
14

Plz solve these both or help explain it

Mathematics
2 answers:
svet-max [94.6K]3 years ago
4 0
Remember to do rise over run in plotting your points to make sure it is a rectangle
Sever21 [200]3 years ago
3 0
Can't you simply graph it?
You might be interested in
An irregular parallelogram rotates 360° about the midpoint of its diagonal. How many times does the image of the parallelogram c
Kazeer [188]

Answer:

2.

Step-by-step explanation:

Rotating a figure about the midpoint of its diagonal, the figure will coincide with its pre-image two times: at 180° and at 360°.

This is different than rotating about the origin; for a rotation about the origin, a 180° rotation does not always coincide with the pre-image.

hope that answers ur question :))))

4 0
3 years ago
Congruent angles have the same ______?​
lapo4ka [179]

Answer:

Congruent angles have the same angle.

8 0
3 years ago
Read 2 more answers
Need help ASAP! Directions in picture ;)
xeze [42]

Answer:

30

Step-by-step explanation:

130 + 20 = 150

All angles added together in a triangle equal 180 so...

180 - 150 = 30

I hope this helps!

8 0
2 years ago
Ramonita gets $4 a week for mowing the lawn. She wants to buy a $9 toy. How many weeks does she need to mow the lawn?
Kaylis [27]

Answer: 3 weeks

Step-by-step explanation: One=4

Second week=8. Bc 4+4=8

third week= 12. Bc 8+4=12

8 0
3 years ago
Find the image of A (-6, 5) after two reflections, first across the line y = -5, then across the
Stolb23 [73]

Answer:

a. A'(-6,-15)

b. A''(-18,-15)

Step-by-step explanation:

The given point is A(-6,5).

We want to find the image after this point has been reflected in the line y=-5.


Recall that, the mapping for a reflection in the line y=k is


P(x,y)\rightarrow P'(x,2k-y).


This implies that,


A(-6,5)\rightarrow A'(-6,2(-5)-5).


This simplifies to,


A(-6,5)\rightarrow A'(-6,-10-5).


This will finally give us,


A(-6,5)\rightarrow A'(-6,-15).


b. We now apply the second reflection, which is a reflection in the line x=-12.


Recall again that, the reflection in the line x=k has the mapping


P(x,y)\rightarrow P'(2k-x,y).


This implies that,

A'(-6,-15)\rightarrow A''(2(-12)--6,-15).

This implies that,

A'(-6,-15)\rightarrow A''(-24+6,-15).


This will finally give us,


A'(-6,-15)\rightarrow A''(-18,-15).


See graph in attachment.






8 0
4 years ago
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