Car A Car B
d=rt d = rt
d = ra * 2.4 d = rb 4
ra = rb+22
distances are the same so set the equations equal
ra * 2.4 =rb *4
substitue in for ra
(rb+22) 2.4 =rb *4
distribute
2.4 rb +52.8 = 4 rb
subtract 2.4 rb from each side
52.8 = 1.6 rb
33 = rb
Car b travels at 33 miles per hour
Car a = 33+22
Car a = 55 miles per hour
Answer:
m<RPS = 53 degrees
Step-by-step explanation:
Find the diagram attached
From the diagram shown;
m<QPR + m<RPS = 90
Given that;
m<QPR = x
m<RPS = x+16
Substitute into the formula;
m<QPR + m<RPS = 90
x+x+16 = 90
2x+16 = 90
2x = 90-16
2x = 74
x = 74/2
x = 37degrees
Get m<RPS;
Since m<RPS = x+16
m<RPS = 37 + 16
m<RPS = 53 degrees
Answer:

Step-by-step explanation:
For easy calculations let's use the supplementary angles:






Now lets calculate the magnitude of the vector C:

where:


Finally:

Answer:
2√3π cm
Step-by-step explanation:
area of circle: πr²
area = A²
A =√ 12π
therefore, A = 2 √ 3π
<span>Triangle Exterior Angle Theorem is equal to the sum of the two opposite interior angles. Angle 1 = 60 + 63 = 123 degrees</span>