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Lesechka [4]
3 years ago
15

Question: The mean birth weight of male babies born to 121 mothers taking a vitamin supplement is 3.67 kilograms (based on New Y

ork department of health data). The national average birth weight of male babies 3.39 kilograms.
Discuss the significance of the sample observation given that the probability of observing such a .sample estimated to be 0.0015
Mathematics
1 answer:
kolezko [41]3 years ago
7 0

Answer:

The significance of the sample is that at it is statistically significant at 0.01 level ( i.e. of observing the sample < 0.01 )

Step-by-step explanation:

The sample observation which is 121 mothers that take vitamin supplements have male babies with mean weight of : 3.67 kg

while the National average birth weight = 3.39 kg

probability of observing such a sample = 0.0015

Hence the significance of the sample is that at it is statistically significant at 0.01 level ( i.e. of observing the sample < 0.01 )

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FromTheMoon [43]

Answer:

Step-by-step explanation:

10/7 x 9/8 = 90/56 = 45/28.

7/9 x 8/10 = 56/90 = 28/45

If you want to multiply these, the answer is (28*45) / 28/45) = 1.

5 0
2 years ago
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Question 1 help pls ​
Evgesh-ka [11]

Answer:

y = - \frac{1}{2} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = \frac{0-2}{4-0} = \frac{-2}{4} = - \frac{1}{2}

note the line crosses the y- axis at (0, 2) ⇒ c = 2

y = - \frac{1}{2} x + 2 ← equation of line

4 0
3 years ago
A rectangular pool has a width of 24 feet. A second rectangular pool has a perimeter of 48 feet, which
Alina [70]

Answer:

Let x = the length

Let P = the perimeter of the first pool

48 = (1/3)P

144 feet = P

P = 2l + 2w

144 = 2x + 2(24)

144 = 2x + 48

96 = 2x

48 feet = x

5 0
3 years ago
Find all solutions to the differential equation dy dt = 1 − y 2
klemol [59]
Try this:
\frac{dy}{dt}=1-y^2; \ =\ \textgreater \  \   \frac{dy}{y^2-1}=-dt; \ =\ \textgreater \  \ ln| \frac{y-1}{y+1}|=-2t+C.
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7 0
3 years ago
Does the point (-1, 2) make the following equations true? i) y = -2x ii) y = x + 3
lesya [120]

Answer:

i) True

ii) True

Step-by-step explanation:

<u>Given :-</u>

Point (-1, 2)

<u>To Find :</u>

Whether the point is a solution of :

  1. y = -2x
  2. y = x + 3

<u>Solving :-</u>

Substitute the value of the point in each of the equations.

=> y = -2x

=> 2 = -2(-1)

=> 2 = 2 [∴ The point makes it true]

=> y = x + 3

=> 2 = -1 + 3

=> 2 =  2 [∴ The point makes it true]

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2 years ago
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