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2 years ago

Help me !! 10/7 x 9/8 7/9 x 8/10

Mathematics

2 answers:

Vlada [557]2 years ago

8 0

Answer:

((((10 / 7) * 9) / 8 7/9) * 8) / 10 = 1.17179024

fraction: 7323689 / 6250000

decmal:1.17179024

FromTheMoon [43]2 years ago

5 0

Answer:

Step-by-step explanation:

10/7 x 9/8 = 90/56 = 45/28.

7/9 x 8/10 = 56/90 = 28/45

If you want to multiply these, the answer is (28*45) / 28/45) = 1.

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(NECESITO PROCEDIMIENTO) 9x + 8 = 7x + 6 X= -1 X= 1/3 X= 1

Aloiza [94]

Answer:

$x=-1$

Step-by-step explanation:

$9x+8=7x+6$

Keep the variables in the left side & rest in the left side:

$9x-7x=6-8$

$2x=-2$

$x=-2/2$

$x=-1$

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3 years ago

Of the students on the track team, 1twelve do the high jump. Of those students 1fourth alsobdo of the long jump. What fraction o

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1/3 fraction of the students have done both

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3 years ago

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Military radar and missile detection systems are designed to warn a coutry of an enemy attack. Assume that a particular detectio

Tom [10]

Answer:

0.96 = 96% probability that at least one of them detect an enemy attack.

Step-by-step explanation:

For each radar, there are only two possible outcomes. Either it detects the attack, or it does not. The missiles are operated independently, which means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Assume that a particular detection system has a 0.80 probability of detecting a missile attack.

This means that $p = 0.8$

If two military radars are installed in two different areas and they operate independently, the probability that at least one of them detect an enemy attack is

This is $P(X \geq 1)$ when $n = 2$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.8)^{0}.(0.2)^{2} = 0.04$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.04 = 0.96$

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6 0

3 years ago

I'm stuck on these can someone help me and show the work please

crimeas [40]

7.) 4 (-2) 12 I multiply 4 by -2 which gives me
-8 = 12 so it is a no solution

8.) 39 - 3 = -6 (4-3)
first u want to multiply the -6 by four and the -6 by the -3 which gives you :
39 - 3 = -24 + 18
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3 0

3 years ago

B(n)=-4-2(n-1) find the12th term in the sequence

bixtya [17]

Answer:

The 12th term in the sequence is b(12)= -26

Step-by-step explanation:

For the 12th term, that means we need to find what the value of b is when n=12

To find b:

Substitute all 'n' with 12 (since its the 12th term)

b(n)= -4-2(n-1)

b(12)= -4-2(12-1)

Solve the equation in order of BEDMAS (aka PEDMAS)

b(12)= -4-2(11)

= -4- (2*11)

= -4-(22)

= -26

The 12th term in the sequence is b(12)= -26

4 0

3 years ago

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