Answer:
I do not agree because Mario's claim is not general.
Step-by-step explanation:
Prime numbers: These are a set of numbers that are divisible by 1 and itself only. Examples are: 2, 3, 5, 7. 11 etc.
And a denominator is the divisor in a given fraction.
Considering the following fractions whose denominators are prime numbers:
= 0.66666666...
= 0.142857142
= 0.45454545...
= 0.23076923
= 0.142857142
It could be observed that Mario's claim is not a general principle which is applicable to all fractions with a prime denominator. Thus, I do not agree with his claim.
Answer:
B
Step-by-step explanation:
So remember that a quarter of a circle is 90 degrees, a half of a circle is 180 degrees, and a whole circle is 360 degrees.
Looking at the image shown, it must be half a circle, whihc is 180 degrees. The image tells us that the 1st angle is 7 degrees. Now, we must find the 2nd angle.
Heres what we know however:
angle 1 + angle 2 = 180 degrees.
How do we know this?
Well, there are only 2 angles in this 180 degrees. We know that the first one is 7 degrees.
Lets input that into our nice lil equation to get an answer:
7 degrees+angle 2 = 180 degrees
Now lets solve.
Subtract 7 on both sides, and your left with:
angle 2 = 173 degrees.
So the answer must be:
<u>173 degrees</u>
Hope this helps! ;)
Answer:
I'll answer one question
Step-by-step explanation:
a. x >= -4. This reads, the domain is greater than and equal to negative four to infinity.
When I took the test, I selected "C. an arrangement in which you receive money now and pay it back later with fees" but I got it wrong. So I'm pretty sure the answer is "A. an arrangement in which you receive money, goods, or services now in exchange for the promise of payment later"
The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>
From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
Read more about Similar Triangles at; brainly.com/question/14285697
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