Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:
Yes
Step-by-step explanation:
0s after all the decimals do not count
The answer should be
_
.16
No it’s not the square root of 32 is 5.65685424949
The chance is 50% because if there are 2 children the probability would be 1/2 or 50%.
