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Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ =
L.H.S = sin θ cos θ
so, sin θ cos θ ≠
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
Equation of line parallel to y = -0.75x that passes through (8,0) is: y = -0.75x-6
Step-by-step explanation:
Given equation of line is:
The coefficient of x is the slope of the line so the slope of given line is: -0.75
As parallel lines have equal slopes so the required equation of line will have the same slope.
The slope-intercept form is:
Putting the value of the slope
To find the value of b, putting the point in the equation
Putting the values of m and b, we get
Hence,
Equation of line parallel to y = -0.75x that passes through (8,0) is: y = -0.75x-6
Keywords: Equation of line, Slope-intercept form
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