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Dennis_Churaev [7]
3 years ago
15

The length of a rectangle is 4 inches less than twice its width. If the area of the rectangle is 70 square inches, what are its

demensions

Mathematics
2 answers:
kykrilka [37]3 years ago
8 0
Let
x-----------> the length side of rectangle
y----------> the width side of rectangle

we know that
70=x*y--------> x=70/y-----------> equation 1
x-4=2y--------> equation 2
substitute equation 1 in equation 2

[70/y]-4=2y--------> multiply by y------> 70-4y=2y²----> 2y²+4y-70=0

using a graph tool ----> to resolve the second order equation
see the attached figure

the solution is 
y=5
x=70/y--------> x=70/5=14

the answer is
the dimensions are
length=14 in
width=5 in

klemol [59]3 years ago
6 0
By definition, the area of a rectangle is given by:
 A = w * l
 Where,
 w: width
 l: long
 Substituting values we have:
 70 = w * (2w-4)
 Rewriting we have:
 70 = 2w ^ 2-4w
 2w ^ 2 - 4w - 70 = 0
 Solving the polynomial we have:
 w1 = -5
 w2 = 7
 We take the positive root because it is a dimension.
 w = 7 inches
 Then, the length will be:
 l = 2w-4
 l = 2 (7) -4
 l = 14-4
 l = 10 inches
 Answer:
 
its demensions are:
 
w = 7 inches
 
l = 10 inches
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allsm [11]

Solving the equation we get:

1\frac{4}{9}-\frac{3}{4}=\frac{52}{\textbf{36}}-\frac{27}{\textbf{36}}=\frac{\textbf{25}}{\textbf{36}}

Step-by-step explanation:

We need to solve the equation: 1\frac{4}{9}-\frac{3}{4}

Solving:

1\frac{4}{9}-\frac{3}{4}

\frac{13}{9}-\frac{3}{4}

Taking LCM of 9 and 4 we get 36

\frac{13*4}{36}-\frac{3*9}{36}

\frac{52}{36}-\frac{27}{36}

\frac{52-27}{36}

\frac{25}{36}

So, solving the equation  1\frac{4}{9}-\frac{3}{4} we get \frac{25}{36}

In the first blank, in denominators we get 36 and in the second black we get \frac{25}{36}

So, answer is:

1\frac{4}{9}-\frac{3}{4}=\frac{52}{\textbf{36}}-\frac{27}{\textbf{36}}=\frac{\textbf{25}}{\textbf{36}}

Keywords: Solving Fractions

Learn more about Solving Fractions at:

  • brainly.com/question/2456302
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#learnwithBrainly

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