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Brut [27]
2 years ago
12

The annual average rainfall in new york is 50 ⅕ inches

Mathematics
1 answer:
marishachu [46]2 years ago
6 0

50.2 should be the anwser i doubled checked with search

and it says it is correct so it should be good.

Step-by-step explanation:

math

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Write an equation for the following problem
Novosadov [1.4K]

Answer:

I believe I know the answer! Please do tell me If I am wrong but math was never my strong sute so tell me If I’m wrong please!

Step-by-step explanation:

8n-15=27 or

(8xn)-15=27

Bonus: n= 5.25 or 5 1/4

(I think)

4 0
2 years ago
Find the area 10yd, 4yd, 10yd, 13yd and 8yd​
kakasveta [241]

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41,600yd's is the area....

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3 years ago
Please Help, I need it for my homework
Naily [24]

Answer:

A)

p1 (0,0) p2 (1,2) given from the graph

slope = (y2-y1)/ (x2-x1 )

slope (m) = 2

y = mx+ b

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y = 2x

b)

x = 0

y = 5

(0,5)

C)

gradient = slope

y = 3x + b

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5 0
2 years ago
Read 2 more answers
Help. Explain good for brainliest
Nimfa-mama [501]

The measure of m∠J=90°, m∠G=55° and m∠H=35°

Step-by-step explanation:

Inscribed angles subtended by a diameter are right angles. Hence angle GJH =90°

The diameter GH and chord GJ intercepts an arc with a measure of 70°.The measure of an arc of a circle is equal to the measure of the central angle that intercepts the arc. Hence angle GOJ=70°. Radius of circle GO=OJ, which means triangle GOJ is an isosceles triangle thus ∠OJG=∠OGJ =(180° -70°) /2 = 55°. m∠G=55°

m∠H = (180°-(90°+55°) ) = 180° - 145° =35°

Learn More

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8 0
3 years ago
Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180
torisob [31]

I got

-  \frac{6 3}{65}

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

\cos(a - b)  =  \cos(a)  \cos(b)  +  \sin(a)  \sin(b)

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

.

{12}^{2}  +  {y}^{2}  =  {13}^{2}

144 +  {y}^{2}  = 169

25 =  {y}^{2}

y = 5

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

.

( - 3) {}^{2}  +  {x}^{2}  =  {5}^{2}

9 +  {x}^{2}  = 25

{x}^{2}  = 16

x = 4

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

-  \frac{3}{5}  \times  \frac{5}{13}  +   - \frac {4}{5}  \times  \frac{12}{13}

- \frac{15}{65} + (  - \frac{48}{65}  )

-  \frac{63}{65}

Hope this helps

6 0
2 years ago
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