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Colt1911 [192]
3 years ago
11

Please help me! simplify. 5-[-(-20] a. -3 b.3 c.-7 d.7

Mathematics
1 answer:
frosja888 [35]3 years ago
8 0

Im sorry i dont know

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A shirt costs $30 but is on sale for 25% off. How much does the shirt cost after the sale?
FrozenT [24]

Answer:

$22.50

Step-by-step explanation:

Find 25% of 30 and then take away that amount from 30.

6 0
2 years ago
The mean of five numbers is 6 the median is 7 and the mode is 2. What is the answer?
Lady_Fox [76]

Answer:

2,2,7,9,10

mark as brainliest

8 0
3 years ago
Use the point-slope formula to write an equation of the line that passes through (4,10) and has a slope of m= 3. Write the
baherus [9]
Answer:
3x --y -2= 0
Step-by-step explanation:
We have formula Y - y 1 = m ( X --x1) => Y - 10 = 3(X-4)
3X - Y - 2 = 0 Ans .


4 0
2 years ago
What is 1/8 of 16 pls I really need to get this done
KatRina [158]

Answer:

2

Step-by-step explanation:

We take the denominator.

That is 8.

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16÷8=2

3 0
3 years ago
Read 2 more answers
Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
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