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Ivenika [448]
3 years ago
7

PLEASE HELP ME!!! ILL GIVE THE FIRST PERSON BRAINLIEST!!!

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0

Problem 2

Midpoint: Think 1/2. A midpoint cuts a line segment in 1/2 (in this question). That means that the left segment = the right segment. Remember: midpoint means 1/2.

LN is given as 14.

LM is 1/2 the distance of 14

LM = 1/2 * 14

LM = 7

Problem 3

If the midpoint = the 1/2 way point, the two halves are equal. Remember a midpoint divides the 2 parts into 2 EQUAL parts.

4a - 2 = 18          Add 2 to both sides

4a = 18 + 2

4a = 20

a = 20 /4

a = 5

Problem 4

Remember that midpoint means 1/2. That a midpoint cuts a segment into 2 equal segments

Equation

2n + 2 =  5n - 4      

Solve

2n + 2 = 5n - 4      Add 4 to both sides

2n + 2 + 4 = 5n     Subtract 2n from both sides.

6 = 5n - 2n

6 = 3n                    Divide both sides by 3

6/3 = n

n = 2

<u>Answer:</u> B

Problem 5

And again the whole line segment is divided into 2 equal parts.

<u>Equation</u>

6p - 12 = 4p           Add 12 to both sides

6p = 12 + 4p           Subtract 4p from both sides.

6p - 4p = 12

2p = 12                   Divide by 2

p = 12/2

p = 6           <<<<< Answer


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Which of the following describes how to translate the graph y = |x| to obtain the graph of y = |x - 6|?. . . shift 6 units up. s
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Answer:

Shift 6 units right.

Step-by-step explanation:

Easiest way to answer this question is to plot the two graphs:

Let's plot these graphs and analyse each graph.

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We can clearly see that graph intersects x axis at x=0 and then essentially looks like y=x is mirrored by the y axis.

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We can see that graph intersects x axis at x=6 and is a composite graph of y=|x-6| and its mirrored graph by y=6.

We can clearly see that graph has moved 6 units to the right.

8 0
3 years ago
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In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

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D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

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