Answer:
2.96 × 10^4 N
Explanation:
1 atm = 101325 N/m², pressure inside the airtight room = 1.02 atm, pressure outside due to hurricane = 0.91 atm
net pressure directed outward = P inside - P outside
net pressure = 1.02 - 0.91 = 0.11 atm
where 1 atm = 101325N/m²
0.11 atm = 0.11 × 101325 N/m² = 11145.75 N/m²
area of the square wall = l × l where l is the length of the wall in meters = 1.63 × 1.63 = 2.6569
net pressure = net force / area
make net force subject of the formula
net force = net pressure × area = 11145.75 × 2.6569 = 2.96 × 10 ^4 N
Answer:
Yes.
Explanation:
Displacement is a vector quantity, meaning it has to be a straight graph jointing from starting point to final point and has a direction as well as magnitude and it can also be negative as well as positive and zero.
Displacement is also changes in position (points) of distance. A distance is scalar quantity meaning it only has magnitude and does not have direction. Since distance is scalar quantity, it cannot be negative. Also graph of distance can be a curve graph or any graph.
So when does displacement equal to distance? If an object is moving in straight path or line in one/fixed direction, both displacement and distance are same.
Because if a distance is a straight path and the displacement is simply a straight line (or ray) jointing from starting point to end point, both distance and displacement are both straight path or rays. Since distance and displacement have same graph, we can conclude that both are same in values.
If we go by calculus, given x = 2t as example of straight graph where x stands for position and t stands for time. We can find the displacement from b to a by using the following formulas:
<u>Displacement</u>
<u /><u />
<u>Distance</u>
<u /><u />
v stands for velocity which we can find from:
<u>Velocity</u>
<u /><u />
If you have learnt calculus, first, differentiate x = 2t with respect to t.
Then substitute v = 2 in s and l to find find if both displacement and distance are equal in straight path.
<u>Displacement</u>
<u /><u />
<u>Distance</u>
<u /><u />
Since both displacement and distance are equal when integrating on straight graph, we can conclude that an object moving in straight fixed point has same distance and displacement.
(a) 147,500 J
Newton's second law, applied to the helicopter, states that
where
F is the lifting force
mg is the weight of the helicopter, with m=500 kg being the mass of the helicopter and g=9.8 m/s^2 the acceleration due to gravity
a=2.00 m/s^2 is the acceleration of the helicopter
From the equation, we can calculate the magnitude of the lifting force:
The vertical distance covered by the helicopter is given by
So, the work done by the lifting force F is
2) -122,500 J
The magnitude of the gravitational force acting on the helicopter is
And the work done by this force on the helicopter is
And the negative sign is due to the fact that the direction of the gravitational force is opposite to the displacement of the helicopter.
3) 25,500 J
The net work done on the helicopter is given by the sum of the work done by the two forces:
You should back-up your computer every few weeks (or as often as needed).
As soon as you suspect that your computer (or any other backup-able device) is too slow or "glitch-y" you should back-up your device before you lose any important files or data.
PREVENTING MALFUNCTION:
→ Always set your computer on a hard & flat surface.
→ Avoid downloading programs from unknown or non-trusted sources.
→ Avoid using your computer in a hot area.
→ Consider installing a virus/malware protection software on your computer.