Which of the following changes will increase the frequency of an oscillating pendulum?
1 answer:
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Answer:
a) K = 2/3 π G m ρ R₁³ / R₂ , b) U = - G m M / r
Explanation:
The law of universal gravitation is
F = G m M / r²
Part A
Let's use Newton's second law
F = m a
The acceleration is centripetal
a = v² / R₂
G m M / R₂² = m v² / R₂
v² = G M / R₂
They give us the density of the planet
ρ = M / V
V = 4/3 π R₁³
M = ρ V
M = ρ 4/3 π R₁³
v² = 4/3 π G ρ R₁³ / R₂
K = ½ m v²
K = ½ m (4/3 π G ρ R₁³ / R₂)
K = 2/3 π G m ρ R₁³ / R₂
Part B
Potential energy and strength are related
F = - dU / dr
∫ dU = - ∫ F. dr
The force was directed towards the center and the vector r outwards therefore there is an angle of 180º between the two cos 180 = -1
U- U₀ = G m M ∫ dr / r²
U - U₀ = G m M (- r⁻¹)
We evaluate for
U - U₀ = -G m M (1 / - 1 /
)
They indicate that for ri = ∞ U₀ = 0
U = - G m M / r
516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.
By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river (), in megawatts:
(1)
Where:
- Efficiency.
- Electric power, in megawatts.
If we know that and
, then the energy rate exhausted to the river is:
516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.
We kindly to check this question on first law of thermodynamics: brainly.com/question/3808473