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4vir4ik [10]
3 years ago
15

Don’t answer this i accidentally made a question and I don’t know how to delete it so yea

Mathematics
1 answer:
IrinaK [193]3 years ago
8 0
Sheeshhhhhhhhhhhhhhhhhhhhhh
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Find the sum or difference.<br>81-3<br>3​
yuradex [85]

Answer:

48

Step-by-step explanation:

81 - 33 = 48

8 0
3 years ago
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Free Bpoints because I'm dripped out in success
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why thank you :)

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Sally painted a picture that has an area of 480 square inches. The length of the painting is 1 1/5 as long as it is wide. What a
marishachu [46]
So Length * Width = 480 in. sq.
L=1 1/5 or 1.2W
substitute the L for 1.2W
1.2W*W=480 in sq
divide both sides by 1.2
w*w= 400
W²=400
square root of both sides
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3 years ago
-3(y-5) simplify please
d1i1m1o1n [39]
Im pretty sure its 8y because two negatives equal a positive so 5 plus 3 and then you isolated the y so 8y. :)
5 0
2 years ago
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One parent is a cystic fibrosis carrier, and the other has
Marysya12 [62]

Answer:

A - 0%

B- 50%

C- 50%

D- 100%

Step-by-step explanation:

Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.

Performing the cross of Aa x AA, we can see that:

a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.

b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.

c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.

d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.

5 0
3 years ago
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