A waterborne pollutant can have different effects on aquatic life depending on the nature of the pollutant. A pollutant at lower levels can have minimal or no effect on aquatic life. However, when the concentrations of the pollutant are high, the population of aquatic organisms can be greatly reduced. There are also times when pollutants at lower concentrations cause significant damage. An organism can consume another organism that has absorbed small amounts of the pollutant. As the consumer takes in more of the contaminated organism, the pollutant is magnified in the body of the consumer resulting in lethal concentrations. This is called biomagnification.
The answer is 0 percent.
If we represent dominant trait (wrinkled seeds) with A and recessive trait (non-wrinkled seeds) with a, then genotypes are AA (dominant homozygous), Aa (heterozygous), and aa (recessive homozygous). The phenotype of wrinkled seed is determined by genotypes either Aa or AA. Since the cross of a plant with wrinkled seed with a plant with non-wrinkled sees gives only wrinkled-seeded offspring, the plant with wrinkled seeds must be dominant heterozygous.
Let's look at both examples.
If wrinked-seeded parent contains one non-wrinkled allele, it must be heterozygous (Aa):
Parents: Aa x aa
Offspring: Aa Aa aa aa
So, the 50% of offspring has wrinkled seeds and 50% has <span>non-wrinkled seeds.
If </span><span>the wrinkled-seeded parent does not contain any non-wrinkled allele:
</span>Parents: AA x aa
Offspring: Aa<span> Aa Aa Aa
</span><span>
Thus, al</span><span>l of the offspring are heterozygous and all of them have wrinkled seeds.</span>
Prokaryotic cells are simple cells that lack membrane-bound nuclei and complex organelles. Endoplasmic reticulum, microtubules, and the Golgi apparatus are unique to eukaryotic cells, and will not be found in prokaryotes.
i hope this helps you
D. Males that only survive to produce sperm