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pantera1 [17]
3 years ago
12

Answer the two questions below. Show ALL of your work.(a) John and Stan were building a sand castle. They decided to make it int

o a cone shape. After some time, the diameter of the sand shaped cone was 12 in and the height was 7in. What is the exact volume of the sand cone? (Show your work. Remember you can draw a picture to help you solve the problem.)
(b) The boys kept adding sand, and ten minutes later the volume of the sand cone had increased by 30%. What is the exact volume of the sand cone now? (Show your work. Remember you can draw a picture to help you solve the problem.)
Math | Graded Assignment | Unit Test, Part 2 | Volume
Mathematics
1 answer:
RoseWind [281]3 years ago
5 0

Answer:

a) 84π b) 109.2π

Step-by-step explanation:

The formula to find this is v=πr^2h/3

r=d/2. so the radius (r) is 6 because you have to divide the diameter (12) by 2. and the height is 7. so, 6^2=36 and 36x7=252.

252/3=84

and because the question is asking for the EXACT value, you need to just put the pi symbol next to it. Final answer for a is 84π

B) you need to find 30% of 84, which is 25.2 and add it to 84, and you will get 109.2! Final answer is 109.2π.

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A cube with a volume of 75 cm³ is dilated by a factor of 5.
Brrunno [24]
ANSWER

The volume of the dilated cube is 9375cm³.


EXPLANATION

The volume of the original cube is 75 cm³.



The scale factor for the dilation is 5.


The scale factor for volume is 5³=125


We multiply the volume of the original cube by 125 to obtain the volume of the dilated cube.


The volume of the dilated cube is

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3 years ago
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The low temperature on Monday was 16°F. On Tuesday, the low was 18°F cooler. On Wednesday, the low temperature was –4 times Tues
drek231 [11]

Answer:

-4(16-18), [16 + (-18)](-4)

Step-by-step explanation:

Given: The low temperature on Monday was 16°F. The low temperature on Tuesday was 18°F cooler. The low temperature on Wednesday was –4 times Tuesday’s temperature.

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Temperature on Monday = 16°F

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Temperature on Wednesday = -4(16-18)\°F

So, expression -4(16-18)=(16-18)(-4) can be used to describe the low temperature on Wednesday.

Also,

(16-18)(-4)=[16 + (-18)](-4)\,\,\left \{\because  (a-b)=\left [ a+(-b) \right ] \right \}

So, expression [16 + (-18)](-4) also represent temperature on Wednesday.

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