Cos( A + B ) = cosAcosB - sinAsinB ;
cos( A + B ) / ( cosAsinB ) = ( cosAcosB - sinAsinB ) / ( cosAsinB ) = ( cosAcosB ) / ( cosAsinB ) - ( sinAsinB ) / ( cosAsinB ) = cosB / sinB - sinA / cosA = cotB - tanA ;
Answer:
I think PR = 20 but I'm not sure
Answer:
The distance between A(-8, 4) and B(4, -1) is 13 units.
Step-by-step explanation:
To find the distance between any two points, we can use the distance formula given by:

We have the two points A(-8, 4) and B(4, -1). Let A(-8, 4) be (<em>x₁, y₁</em>) and let B(4, -1) be (<em>x₂, y₂</em>). Substitute:

Evaluate:

So:

The distance between A(-8, 4) and B(4, -1) is 13 units.
The answer for the first on 8 and the second one is 9
Answer:
16
Step-by-step explanation:
2*8= 16