The answer to the questions of volumes are given as follows
a) 
b) 
c)
d)
Generally, the questions are mathematically solved below

a) x-axis
if $y=4, x=16, x=0$
Using disk method




b) line y=4
if x=0, y=0 ;

Using shell method


![v=2 \pi\left[\frac{4 y^{3}}{3}-\frac{y^{4}}{4}\right]_{0}^{4} \\](https://tex.z-dn.net/?f=v%3D2%20%5Cpi%5Cleft%5B%5Cfrac%7B4%20y%5E%7B3%7D%7D%7B3%7D-%5Cfrac%7By%5E%7B4%7D%7D%7B4%7D%5Cright%5D_%7B0%7D%5E%7B4%7D%20%5C%5C)
![v=\frac{2 \pi}{12}[1024-768] \\](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B2%20%5Cpi%7D%7B12%7D%5B1024-768%5D%20%5C%5C)


c) y-axis
0 ≤ y ≤ 4
x=y^2
Using disk method
volume



d) line x=-1
y=√x, y=4, x=0
0 ≤ x ≤ 6
Using shell method
volume is


![V=2 \pi\left[\frac{x^{3 / 2}}{3 / 2}+\frac{x^{5 / 2}}{5 / 2}\right]_{0}^{16} \\](https://tex.z-dn.net/?f=V%3D2%20%5Cpi%5Cleft%5B%5Cfrac%7Bx%5E%7B3%20%2F%202%7D%7D%7B3%20%2F%202%7D%2B%5Cfrac%7Bx%5E%7B5%20%2F%202%7D%7D%7B5%20%2F%202%7D%5Cright%5D_%7B0%7D%5E%7B16%7D%20%5C%5C)
![V=2 \pi\left[2 / 3 \cdot\left(4^{2}\right)^{3 / 2}+2 / 5\left(4^{2}\right)^{5 / 2}\right] \\](https://tex.z-dn.net/?f=V%3D2%20%5Cpi%5Cleft%5B2%20%2F%203%20%5Ccdot%5Cleft%284%5E%7B2%7D%5Cright%29%5E%7B3%20%2F%202%7D%2B2%20%2F%205%5Cleft%284%5E%7B2%7D%5Cright%29%5E%7B5%20%2F%202%7D%5Cright%5D%20%5C%5C)





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There are 6 outcomes for the cube and 4 for the spinner. So you can multiply 6 and 4. That gives you 24. The answer is C. 24. Hope this helps!
C (3,1)
There is the answer and also a check to make sure hope this helps
Answers:

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Explanation:
By definition, 
Squaring both sides gets us 
Then multiply both sides by i to get 
Repeat the last step and you should get 
---------------
Notice we have this pattern going on:

Once we reach i^4, we start the process over again.
It repeats every 4 terms.
This means we'll divide the exponent over 4 and look at the remainder. We ignore the quotient completely.
157/4 = 39 remainder 1
That remainder 1 is the exponent of the simplified term

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Similarly,
315/4 = 78 remainder 3
So 
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102/4 = 25 remainder 2

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76/4 = 19 remainder 0
