What score does jane need to receive an 85% average if she has an 32,90,92,82,64

Mathematics

2 answers:

topjm [15]3 years ago

5 0

(32 + 90 + 92 + 82 + 64 + x) / 6 = 85
(360 + x) / 6 = 85
360 + x = 85 * 6
360 + x = 510
x = 510 - 360
x = 150 <===

boyakko [2]3 years ago

5 0

(P+32+90+92+82+64)÷6 = 85
P + 360 = 85*6
P + 360 = 510
P = 510 - 360
P = 150

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Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

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The pentagon MNPQR has a perimeter of 22 units.

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Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

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$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$