Answer:
In solving a system of linear equations, we try to find values for each of the unknowns that will satisfy every equation in the system
Step-by-step explanation:
An excluded value is one where the bottom of the fraction = 0.
In your case 1-3x=0
1=3x
x=1/3
At this point, the function does not exist. If you were to draw a graph of it, there wouldn't be a y-value corresponding to x=1/3.
This can be determined by finding the x-intercept. In doing so, we let y=0 to find the value of x.
y= 2x^2 -x -3
[0 = 2x^2 -x-3]÷2
0 = x^2 -1/2 x - 3/2
Complete the squares:
1/16 + 3/2 = x^2 - 1/2x + 1/16
25/16 = (x -1/4)^2
sqrt (25/16) = x - 1/4
+/- 5/4 = x - 1/4
Thus,
x = 1/4 + 5/4 = 3/2
x = 1/4 - 5/4 = -1
Thus, the graph crosses at x = 3/2 and x = -1.
Unit cost of a ticket = Income from ticket sales / number of tickets sold:
$1250
--------------- = $6.58 per ticket
190 tickets
Again:
$1175
--------------- = $6.71
175 tickets
While ticket prices do change (usually increase) from year to year, it's unusual to see such a situation here.
Don't have any guidelines by which to determine the "fixed cost of a ticket".
If we use the cost of a ticket of 2 years ago ($6.58/ticket), then the income from the sale of 225 tickets this year would be ($6.58/ticket)(225 tickets), or $1480.50.
Notice that <em>f(x)</em> is only defined over the intervals 0 ≤ <em>x</em> < 3 and 3 < <em>x</em> ≤ 6; that is, all real numbers <em>x</em> between 0 and 3, and between 3 and 6, but <u>not including 3</u>. Since there is no definition for <em>f(x)</em> at <em>x</em> = 3, the value of <em>f</em> (3) is undefined.
