Answer:
no pictur no answer
Step-by-step explanation:
Put it in the form
ax^2 + bx + c = 0
use the quadratic formula
x = [ -b + sqrt( b^2 - 4 ac ) ] / 2a
x = [ -b - sqrt( b^2 - 4 ac ) ] / 2a
7v^2 - 7v - 22 = 0
a = 7
b = -7
c = -22
v = [ 7 + sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = 2.34
v = [ 7 - sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = -1.34
C=x+9, c+x=99, c=99-x
So we have two equations equal to c, c=x+9 and c=99-x, since c=c:
x+9=99-x
2x+9=99
2x=90
x=45, and since c=x+9, c=54
So Charlie weighs 54 kg and his brother weighs 45 kg.
Answer:
point G : (7,4)
point F : (7,1)
point J : (2,4)
point H: (5,4)
Step-by-steWhen you translate you take each point and move it how many units it asks you to move. In this problen you move each point 7 units to the right and 9 units up to get your answer.
Answer:
The radius of a sphere is 2 millimeters
The surface area of a sphere is 50.24 square millimeters.
The circumference of the great circle of a sphere is 12.56 millimeters.
Step-by-step explanation:
<u><em>Verify each statement</em></u>
case A) The radius of a sphere is 8 millimeters
The statement is false
we know that
The volume of the sphere is equal to

we have


substitute and solve for r


case B) The radius of a sphere is 2 millimeters
The statement is True
(see the case A)
case C) The circumference of the great circle of a sphere is 9.42 square millimeters
The statement is false
The units of the circumference is millimeters not square millimeters
The circumference is equal to

we have

substitute


case D) The surface area of a sphere is 50.24 square millimeters.
The statement is True
Because
The surface area of the sphere is equal to

we have

substitute


case E) The circumference of the great circle of a sphere is 12.56 millimeters.
The statement is true
see the case C
case F) The surface area of a sphere is 25.12 square millimeters
The statement is false
because the surface area of the sphere is 
see the case D