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konstantin123 [22]
2 years ago
8

What is the cost in dollars and cents for each chocolate bar?

Mathematics
1 answer:
gogolik [260]2 years ago
5 0

Answer:

$1.45

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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Find the mean of the data in the bar chart below.
Snowcat [4.5K]
<h2>Answer:</h2>

12

<h2>Step-by-step explanation:</h2>

<u><em>The mean is also the average.</em></u>

Add up all the number of students all together:

12+13+14+9

48

Now, Divide the total amount of students (48) by the amount of numbers you added (in this case, 48/4 because we added 4 numbers wich are 12+13+14+9)

The average amount of students is 12

7 0
3 years ago
Please please help, i will mark the brainliest
Bumek [7]

Answer:

58

Step-by-step explanation:

i think this is the right answer. Not sure

6 0
3 years ago
Read 2 more answers
114% of 145 is what number​
Elanso [62]

Answer:

165.3

Step-by-step explanation:

8 0
3 years ago
A time/motion word problem
andriy [413]
The two planes are flying on the two legs of a right triangle.
The straight distance between them is the hypotenuse of the triangle.

Since the speeds are in mph, let's work the time in hours.
Call the time 'H' that we're looking for.
It's the number of hours after they both take off that they're 650 miles apart.

After 'H' hours, the first plane has gone 500H miles north.
After 'H' hours, the second plane has gone 1200H miles east.
After 'H' hours, they are 650 miles apart.

Do you remember this for a right triangle ? ==>    A² + B² = C²

(500H)² + (1200H)² = (650)²

250,000H² + 1,440,000H² = 422,500

1,690,000 H² = 422,500

H² = (422,500) / (1,690,000) = 0.25

H = √0.25 = 1/2 hour = 30 minutes
3 0
3 years ago
Read 2 more answers
A data analyst has spreadsheets numbered
algol [13]

Answer:

\frac{2}{9}

Step-by-step explanation:

{\textrm}{Total number of objects here} = 9

(2 spreadsheets, 3 databases and 4 presentations,

{\textrm}({Total} = 2+3+4 = 9)

{\textrm}{No. of databases with an odd number} = 2 {\textrm}{(databases with number 1 and 3})

As  not mentioned other wise equal chances of all the outcomes is assumed so, by the classical definition of probability,

P(The chosen item is a odd numbered database)

=\frac{2}{9}

8 0
3 years ago
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