1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eva8 [605]
4 years ago
6

Mitchell wants to order CDs on the Internet. Each CD costs $15.99, and shipping for the entire order is $9.99. Mitchell has no m

ore than $100 to spend. What is the maximum number of CDs that Mitchell can order?
Mathematics
2 answers:
katovenus [111]4 years ago
8 0

Answer:

maximum 5 CDs

Step-by-step explanation:

Let Mitchell can order a maximum of x CDs

It has been given that each CD costs $15.99, and shipping for the entire order is $9.99.

Thus, we have the total cost for x CDs

15.99x+9.99

Now, Mitchell has no more than $100 to spend. It means

15.99x+9.99

Subtract 9.99 to both sides

15.99x

Divide both sides by 15.99

x

Hence, Mitchell can order maximum 5 CDs

gogolik [260]4 years ago
4 0
<h2>Hello!</h2>

The answer is: Mitchell can order a maximum of 5 CDs.

<h2>Why?</h2>

Let's make the entire shipping cost apart to calculate the actual money amount Mitchell could spend just buying CDs,

Money To Spend = CDsPrice+ShippingPrice\\100=CDsPrice+9,99\\CDsPrice=100-9,99=90,1

So, he will be able to spend 90,1 $

In order to calculate how many CDs Mitchell could buy with 90,1$, she/he should divide the total available amount by the CDs price which is 15,99$

Doing the calculation we have:

\frac{90,1}{15,99} = 5,62

So, since a CD is an indivisible object,  Mitchell can order a maximum of 5 CDs.

Have a nice day!

You might be interested in
ABCDEFGHIJ is a regular decagon with a radius of 25.89 units. Find the area of ABCDEFGHIJ. Round the answer to the nearest tenth
Verdich [7]
Let's call the midpoint of GF M.
MF = 16/2 = 8
KF = 25.89
MK = sqrt(25.89^2 - 8^2)
MK = 24.62
MKF = 8 * 24.62 / 2 = 98.48 square units for one triangle
There are 20 of those triangles that make up the decagon.
Therefore the total area = 20(98.48) = 1969.6 which would be option C
 
6 0
3 years ago
What are the whole steps to get the answer for 4x -6=x +9?
lesantik [10]
First do -x then -x to 4x so you have 3x-6=9.
Add 6 to -6 to cancel it out, then add 6 to 9.
3x-6. Divide 3from x, divide 3from 6. X=2. Plz answer my question too plz
6 0
3 years ago
Read 2 more answers
9. After a mild heart attack, Mary spent 3 days in a coronary care unit. Her
Ulleksa [173]
$966 was her daily room rate.
3 0
3 years ago
Complete the statement. If a transversal intersects two parallel lines, then ___.
almond37 [142]

Answer:

alternate interior angles are always congruent.

Step-by-step explanation:

- Consecutive [Same-side] exterior angles are always supplementary.

- Consecutive [Same-side] interior angles are always supplementary.

- Corresponding angles are always congruent.

I am joyous to assist you anytime.

4 0
3 years ago
Read 2 more answers
This cone has a volume of approximately 1,272.35 squared 2
aliina [53]

Answer: you square aka multiply the volume by itself

Step-by-step explanation:

4 0
4 years ago
Other questions:
  • WILL GIVE BRAINEST <br>If f(x)=5x^2-3....
    8·1 answer
  • Please show working out thanks
    13·1 answer
  • You and your friend are splitting a restaurant bill and leaving a tip. You pay half of the bill plus $5. Your friend pays half o
    8·2 answers
  • Help plzzz..... I don't understand.
    15·2 answers
  • WILL MARK BRAINLIEST!
    7·2 answers
  • I need help with this <br><br> look at picture <br><br> Complementary angles
    12·2 answers
  • Pls I need help I don’t understand this
    11·1 answer
  • PLEASE HELP ASAP !!!!!!
    14·1 answer
  • LIKE I ACTUALLY NEED HELP THIS IS LITERAL TESTING NOT NO QUIZ.
    6·1 answer
  • the table shows the cost of the daycare for Lucy's dog this week her dog went 3 full days of day care and 2 half days of day car
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!