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AleksAgata [21]
3 years ago
15

Dr. Clarence invested $5000 in an account that draws 3.2% interest, compounded annually. What is the total value of the account

after 5 years?
Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0
Given that the amount invested was compounded annually, the total value of the investment after 5 years will be:
FV=P(1+r/100)^n
where:
FV=future value
p=principle
r=rate
n=time
hence
FV=5000(1+3.2/100)^5
FV=$5,852.865
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Divide the following
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\frac{x^{2} - 4}{x - 8} \div \frac{x - 2}{1}
\frac{x^{2} + 2x - 2x - 4}{x - 8} \div \frac{x - 2}{1}
\frac{x(x) + x(2) - 2(x) - 2(2)}{x - 8} \div \frac{x - 2}{1}
\frac{x(x + 2) - 2(x + 2)}{x - 8} \div \frac{x - 2}{1}
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7 0
4 years ago
What is 7(f+3)+9=5(f-2)-3f
muminat

Answer:

f = -8

Step-by-step explanation:

7(f+3)+9=5(f-2)-3f

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7f + 30 = 2f - 10

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8 0
3 years ago
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3 years ago
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Given trapezoid abcd with bases ab and cd, draw diagonals ac and bd. let e be the midpoint of ac and f the midpoint of bd. prove
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Consider the picture.

Let MN be the midsegment of the trapezoid.

That is M is the midpoint of AD, N is the midpoint of BC.

Being the midsegment of the trapezoid, MN is parallel to the bases.


Let O and K be the intersections of the diagonals with the midsegment.




MN//AB, so MO//AB, and since M is the midpoint of DA, O must be the midpoint of DB, 

Similarly we prove that K is the midpoint of CA.

Thus O is F and K is E.

O and K lie on the midsegment MN, so F and E lie on the midsegment.



MO is a midsegment of triangle ABD so |MO|=1/2 |AB|=1/2 * 10=5

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|OK|=|MK|-|MO|=11-5=6 (units)

7 0
4 years ago
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