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yKpoI14uk [10]
3 years ago
14

Write a function that models 40mg of a substance that has a half life of 84 days

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer: The function is M(t) = 40mg*0.992^t

Step-by-step explanation:

Half life refers to the time that a given quantity to reduce to half its initial value.

This is usually a exponential decay, so we want a function of the form:

M(t) = A*r^(*t)

Were t is time, in this case, t is the number of days

A is the initial value

r is the rate of decrease, we will find that for exponential decays r must be a number between 0 and 1. If r is closer to 0, we will have a fast exponential decay, if r is closer to 1 we will have a slower exponential decay.

We have that the initial mass is 40mg, this is at t = 0.

M(0) = A*r^(0) = A = 40mg

So now we have the value of A.

Now, we know that in t = 84, the mass of the substance will be half its initial value, so it will be:

A/2 = 40mg/2 = 20mg

this means that:

M(84) = 40mg*r^(84) = 20mg

r^(84) = 20mg/40mg = 1/2

r = \sqrt[84]{1/2} = 0.992

Then the equation is:

M(t) = 40mg*0.992^t

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students' ratings of their professors' performance on a five-point scale ranging from poor to excellent

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What is the sum of series is numbers 64&amp;66 ?<br> Using the summation notation
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Answer:

64. 6138

66. 8.078125

Step-by-step explanation:

Let's take it one number at a time.

For number 64:

6(2)^{1-1}=6

6(2)^{2-1}=12

6(2)^{3-1}=24

6(2)^{4-1}=48

6(2)^{5-1}=96

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12(-\frac{1}{2})^{1}=-6

12(-\frac{1}{2})^{2}=3

12(-\frac{1}{2})^{3}=-1.5

12(-\frac{1}{2})^{4}=0.75

12(-\frac{1}{2})^{5}=-0.375

12(-\frac{1}{2})^{6}=0.1875

12(-\frac{1}{2})^{7}=-0.0078125

12(-\frac{1}{2})^{8}=0.046875

12(-\frac{1}{2})^{9}=-0.0234375

Sum = 12 + -6 + 3 + -1.5 + 0.75 + -0.375 + 0.1875 + -0.0078125 + 0.046875 + -0.0234375

or to make things simpler:

Sum = 12 - 6 + 3 - 1.5 + 0.75 - 0.375 + 0.1875 - 0.0078125 + 0.046875 - 0.0234375

Sum = 8.078125

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