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klemol [59]
3 years ago
10

Which set of angles form a vertical angle pair?

Mathematics
2 answers:
aleksklad [387]3 years ago
6 0
It’s C I think it must be
SVETLANKA909090 [29]3 years ago
5 0
2 important fact to know about vertical angles:
• they’re always opposite of each other
• they’re always congruent (equal to each other)

Your answer will be:
C - ∠BEA and ∠DEF
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Arethmetic sequence examples
lord [1]

Answer:

1, 4, 7, 10, 13, 16, 19, 22, 25....

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Which of the following statements best describes the effect of replacing the graph of f(x) with the graph of f(x) − 5? (1 point)
-Dominant- [34]
The entire graph is transformed 5 units down
3 0
4 years ago
What is the volume of a cube with an edge length of 3.2 meters?
Llana [10]
3,276.8 cm^3 or 32.768 m^3
3 0
3 years ago
Read 2 more answers
It says to calculate the area of the sector and t round to the nearest hundredth and to use 3.14 for Pi
fenix001 [56]

Answer:

Step-by-step explanation:

The formula for the area of a sector is

A=\frac{\theta}{360}*\pi r^2 where theta is the measure of the central angle (which is the same measure as that of the arc that is intercepted by the 2 radii formig the angle), and r is the radius.

For us, theta is 90 degrees and r is 20. Filling in the formula:

A=\frac{90}{360}*(3.14)(20)^2 which simplifies down a bit to

A=\frac{1256}{4} so

A = 314 m squared

5 0
4 years ago
Determine the general solution of:<br><br> sin 3x - sin x = cos2x
SpyIntel [72]
Sin³ x-sin x=cos ² x

we know that:
sin²x + cos²x=1  ⇒cos²x=1-sin²x
Therefore:

sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0

sin³x=z

z³+z²-z-1=0

we divide by Ruffini method:
              1     1     -1     -1
        1           1      2      1                z=1
-------------------------------------
              1     2      1      0
       -1         -1      -1                       z=-1
--------------------------------------
              1     1       0                       z=-1

Therefore; the solutions are z=-1 and z=1

The solutions are:
if z=-1, then
sin x=-1   ⇒x= arcsin -1=π+2kπ    (180º+360ºK)   K∈Z


if z=1, then
sin x=1   ⇒ x=arcsin 1=π/2 + 2kπ   (90º+360ºK)   k∈Z

π/2 + 2kπ    U   π+2Kπ=π/2+kπ     k∈Z    ≈(90º+180ºK)

Answer: π/2 + Kπ    or     90º+180ºK          K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
6 0
3 years ago
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