To find the length of the diagonals, Troy should use the Pythagorean Theorem. The diagonal is going to be the hypotenuse of the triangle (the side directly across from the 90 degree angle).

a^2 + b^2 = c^2
6^2 + 10 ^2 = c^2
136 = c^2; find the square root of 136
c = 11.66 feet

Troy's diagonals are approximately 11.66 feet.

5 0

3 years ago

If p(x) = X squared -1 and q(x) = 5(x-1), which expression is equivalent to (p-q)(x)

hram777 [196]

Minus the functions
(p-q)(x)=p(x)-q(x)
p(x)= $x^2-1$
q(x)=5(x-1)

p(x)-q(x)= $x^2-1$ -5(x-1)
p(x)-q(x)= $x^2-1$ -5x+5
p(x)-q(x)= $x^2-5x+4$
(p-q)(x)= $x^2-5x+4$
or factored
(p-q)(x)=(x-4)(x-1)

8 0

3 years ago

Last one (for now)

Tasya [4]

Answer: A

Hope this helps :)

5 0

3 years ago

I need help please!!!!!!!​

I need help please!!!!!!!