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2 years ago

Someone please help w image below

Mathematics

1 answer:

Nadusha1986 [10]2 years ago

5 0

Answer:

slope = 0

Step-by-step explanation:

A horizontal line parallel to the x- axis has a slope of zero.

Since the x- axis has a slope of zero, any line parallel to it will also have a slope of zero.

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Complete the fraction that is equivalent to . = ¯¯¯¯¯ 24

wariber [46]

Answer:

24 is equivalent to 24/1

Step-by-step explanation: Hope this helped you feel free to ask questions in comments.

4 0

2 years ago

Solve each equation and check to make sure both solutions work 2|5x-3|+10=4

Ede4ka [16]

If your just looking for x then x=2

7 0

3 years ago

larry ran 220 meters farther that leigh ran. leigh ran 2.3 kilometers. how many kilometers did larry run?

Gala2k [10]

Larry ran 2.52 killometers. Since a meter is 0.001 killometers, you have to do 0.001 x 220 which is 0.22 then do 2.3 + 0.22 and get 2.52.

6 0

3 years ago

Suppose we write the numbers $1,2,3,4,5,6$, and then color each number red or blue. The coloring is called factorific if there i

Oxana [17]

Answer:

The probability that his coloring is factorific is 0.28125

Step-by-step explanation:

For calculate the probability is necessary to identify the total number of ways to color the six number. This can be calculate with the rule of multiplication as:

2*2*2*2*2*2=64

Because we have 2 options to color every number.

For know the number of ways in which the coloring is factorific, first we need to identify the divisors of each number:

1: the divisor is 1

2: The divisors are 2 and 1

3: The divisors are 3 and 1

4: The divisors are 4, 2 and 1

5: The divisors are 5 and 1

6: The divisors are 6, 3 and 1

From these information we analyse that for made a factorific coloring, is necessary that the number 1 is color blue. Additionally if the number 4 is color blue, the number 2 needs to be color blue and if the number 6 is blue, the number 3 needs to be blue.

So, the number of ways in which we can create a factorfic number is determined by the following cases:

The number 2 is blue and the number 3 is blue: In this case we have 1 option for number 1, one for number 2 and 1 for number 3. Taking into account that the number 2 and 3 are blue, if the number 4 and 6 are blue or red doesn't change the fact that the coloring is going to be factorific. So, we have two options for number 3 and 2 options for number 6. Finally the color of the number 5 is independent of the colors of number 2 and 3, so we also have 2 options for coloring number 5 and the coloring is going to be factorific. Then the number of ways for this situation is calculate as:

1 * 1 * 1 * 2 * 2 * 2 = 8

number 1 number 2 number 3 number 4 number 5 number 6

At the same way we can calculate the following cases:

The number 2 is blue and the number 3 is red: If the number 3 is red, the coloring is only going to be factorific is number 6 is red. Then the number of ways for this situation is calculate as:

1 * 1 * 1 * 2 * 2 * 1 = 4

number 1 number 2 number 3 number 4 number 5 number 6

The number 2 is red and the number 3 is red: If the number 2 and 3 are red, the coloring is only going to be factorific is number 4 and 6 are red. Then the number of ways for this situation is calculate as:

1 * 1 * 1 * 1 * 2 * 1 = 2

number 1 number 2 number 3 number 4 number 5 number 6

The number 2 is red and the number 3 is blue: If the number 2 is red, the coloring is only going to be factorific is number 4 is red. Then the number of ways for this situation is calculate as:

1 * 1 * 1 * 1 * 2 * 2 = 4

number 1 number 2 number 3 number 4 number 5 number 6

If we sum all the cases, we obtain 18 ways to make a factorific coloring. So the probability can be calculated as:

$P= \frac{18}{64} = 0.28125$

4 0

3 years ago

Find the length of the leg a of a right triangle with leg length b = 21.5 inches and the hypotenuse c = 31.9 inches. Use a calcu

mylen [45]

The length of the leg a of the right triangle is obtained by applying the Pythagorean theorem which is given as:

$\text{opposite}^2+adjacent^2=hypothenus^2$

Thus, we have that:

$a^2+b^2=c^2$

Given that b = 21.5 inches and c = 31.9 inches, we now have:

$a^2+(21.5)^2=(31.9^2)$ $a^2+462.25=1017.61$ $a^2=1017.61-462.25$ $a^2=555.36$ $\begin{gathered} a=\sqrt[]{555.36}=23.57 \\ \Rightarrow a=23.6\text{ inches (to one decimal place)} \end{gathered}$

Therefore, the length of the leg a of the right triangle is 23.6 inches

4 0

1 year ago