Answer: 0.665.
Step-by-step explanation:
60% of the bags are from supplier A, and 95% of them are undamaged.
40% of the bags are from supplier B, and 75% of them are undamaged.
Then, the number of undamaged bags from supplier A is:
0.6*0.95 = 0.57 or 57%
from B is:
0.4*0.75 = 0.3 or 30%
This means that the percentage of undamaged bags is:
57% + 30% = 87%.
Then, the probability that an undamaged bag is from supplier A is equal to the percentage of undamaged bags that came from supplier A (57%) and the total percentage of undamaged bags (87%) this is:
P = 57%/87% = 0.655 or 65.5%
Then the probability that an undamaged bag comes from supplier A is 0.665.
7500 if your asking how many he drove in may
The probability is 4⋅3⋅2⋅1/10•9•8•7=(4/4)(6/0)/(10/4)=1/210 so the probability of selecting 3 red balls would be 1/210
