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Neporo4naja [7]
3 years ago
13

Find angle PRS in the image above

Mathematics
1 answer:
trasher [3.6K]3 years ago
6 0

Answer:

142°

Step-by-step explanation:

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10cm 3mm - 4.8cm<br> I do not understand that well can someone please help no need to explain
OleMash [197]

Answer:

60mm   or   6cm

Step-by-step explanation:

108mm - 48mm = 60mm

3 0
3 years ago
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A line has a zero slope and
kipiarov [429]
Hello here is a solution : 
equation for the line is : y = ax+b    a : slope 
a = 0
passes through the point (-5, 4) : 4 =0(-5)+b
b= 4
equation for the line is : y =4

3 0
4 years ago
erika estimates that she is 200 to 300 miles away from her destination. if her car travels 25 miles per gallon of gas and each g
DedPeter [7]

Answer:

32$ < x < 48$

Step-by-step explanation:

Erika estimates that her destination is between 200 and 300 miles away.

When we divide 200 with 25 miles we get 200/25 = 8 gallons

When we divide 300 with 25 miles we get 300/25 = 12 gallons

When we multiply 8 · 4 = 32$ we get amount of money for destination

200 miles  x = 32$

When we multiply 12 · 4 = 48$ we get amount of money for destination

300 miles  x = 32$

Since that the estimate destination is between 200 miles and 300 miles

then the best estimate for the amount of money is between

32$ < x < 48$

God with you!!!

7 0
3 years ago
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Solve 3/5=8/y. Round to the nearest tenth. 15.2 9.8 13.3 18.8
Sidana [21]
3/5 = 3/y
40 = 3y
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4 0
4 years ago
Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0
Debora [2.8K]

So, the definite integral  \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Given that

\int\limits^1_0 {x^{2} } \, dx = 13

We find

\int\limits^1_0 {(4 - 6x^{2} )} \, dx

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4    - 6\int\limits^1_0 {x^{2} } \, dx

Since

\int\limits^1_0 {x^{2} } \, dx = 13,

Substituting this into the equation the equation, we have

\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Learn more about definite integrals here:

brainly.com/question/17074932

4 0
2 years ago
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