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3 years ago

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Mathematics

1 answer:

Elena L [17]3 years ago

5 0

Answer:

The answer I got for this equation is x=5

I hope this image helps of showing you how to solve the equation.

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Estimated unit rate of 2.35 and 12 eggs

pychu [463]

Rounded to the nearest hundredth is 0.20 to 1. Hope that helps!

4 0

2 years ago

At what point is the following function continuous?

liubo4ka [24]

Check the picture below.

something worth noticing $\bf \cfrac{x^2-x-6}{x-3}\implies \cfrac{(\underline{x-3})(x+2)}{\underline{x-3}}\implies x+2$

so, we're really graphing x+2, with a hole at x = 3, however, when x = 3, we know that f(x) = 5, but but but, when x = 3, x+2 = 5, so we end up with a continuous line all the way, x ∈ ℝ, because the "hole" from the first subfunction, gets closed off by the second subfunction in the piece-wise.

4 0

3 years ago

The length of the box is x

Romashka [77]

A polynomial that represents the volume of the Amazon box is; V(x) = x³ - 6x² + 5x

<h3>How to calculate the volume of a box</h3>

Length of box = x
Width of the box is 4 inches less than the length. Thus; width = x - 4
Height is said to be 1 inch less than the width. Thus; height = x - 4 - 1 = x - 5

Now, the formula for volume of a box is;

V = length × width × height

Thus;

V = x • (x - 1) • (x - 5)

V = x(x² - x - 5x + 5)

V = x(x² - 6x + 5)

V(x) = x³ - 6x² + 5x

In conclusion, the polynomial that represents the volume of the Amazon box is V(x) = x³ - 6x² + 5x

Read more on volume of a box at; brainly.com/question/15532376

3 0

2 years ago

The acceleration of an object (in m/s^2) is given by the function a(t) = 9 sin(t). The initial velocity of the object is v(0) =

pentagon [3]

a) Acceleration is the derivative of velocity. By the fundamental theorem of calculus,

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

so that

$v(t)=\left(-11\frac{\rm m}{\rm s}\right)+\int_0^t9\sin u\,\mathrm du$

$\boxed{v(t)=-\left(2+9\cos t)\right)\frac{\rm m}{\rm s}}$

b) We get the displacement by integrating the velocity function like above. Assume the object starts at the origin, so that its initial position is $s(0)=0\,\mathrm m$ . Then its displacement over the time interval [0, 3] is

$s(0)+\displaystyle\int_0^3v(t)\,\mathrm dt=-\int_0^3(2+9\cos t)\,\mathrm dt=\boxed{-6-9\sin3}$

c) The total distance traveled is the integral of the absolute value of the velocity function:

$s(0)+\displaystyle\int_0^3|v(t)|\,\mathrm dt$

$v(t)$ for $0\le t$ and $v(t)\ge0$ for $\cos^{-1}\left(-\frac29\right)\le t\le3$ , so we split the integral into two as

$\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}-v(t)\,\mathrm dt+\int_{\cos^{-1}\left(-\frac29\right)}^3v(t)\,\mathrm dt$

$=\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}(2+9\cos t)\,\mathrm dt-\int_{\cos^{-1}\left(-\frac29\right)}^3(2+9\cos t)\,\mathrm dt$

$\displaystyle=\boxed{2\sqrt{77}-6+4\cos^{-1}\left(-\frac29\right)-9\sin3}$

4 0

3 years ago

Write an equation for the line perpendicular to 2x−3y = 5 and containing (−2, 1).

Nostrana [21]

Hello:<span>
the equation is : y = ax+b
the slope is a : a×(2/3) = -1......( perpendicular to a line : 2x-3y =7 with a slope of 2/3 because : y = (2/3)x-7/3)
a = -3/2 y=(-3/2)x+b
the line that passes through (-2, 1) : 1 = (-3/2)(-2)+b
b = -2
<span> the equation is : y = (-3/2)x-2</span></span>

8 0

3 years ago