Match each equation with its solution.

Mathematics

2 answers:

Lady_Fox [76]2 years ago

8 0

Answer:

a.2 b.10 c.-10 d.-0.4

Step-by-step explanation:

hope this helps

Aleksandr-060686 [28]2 years ago

5 0

Answer:the first one is ten And the last one is the first one on top

Step-by-step explanation:

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You have $55,000 in savings account that pays 2% intrest per year. The inflation rate that year is 3.24%. How much do you make i

Sever21 [200]

Your interest formula is given to you.

Interest in a year = principal (the amount invested) * rate (the interest rate) * period (the time you're measuring)

Interest = 55,000 * 2% * 1 year = 55,000 * 0.02 * 1 = $1,100

How much would you need to have made for your spending power to keep with inflation? Your interest rate would have needed to match the inflation rate, otherwise prices are going up faster than you're saving.

Required interest = 55,000 * 3.24% * 1 year = 55,000 * 0.0324 * 1 = $1,782

How much buying power did you lose? The difference between your required interest and your actual interest.
Buying power lost = 1,782 - 1,100 = $682. You lost this much in buying power.

Hope that helped :)

6 0

2 years ago

According to the last census (2010), the mean number of people per household in the United States is LaTeX: \mu = 2.58 Assume a

Veseljchak [2.6K]

Answer:

P(2.50 < Xbar < 2.66) = 0.046

Step-by-step explanation:

We are given that Population Mean, $\mu$ = 2.58 and Standard deviation, $\sigma$ = 0.75

Also, a random sample (n) of 110 households is taken.

Let Xbar = sample mean household size

The z score probability distribution for sample mean is give by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)

P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar $\leq$ 2.50)

P(Xbar < 2.66) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{2.66-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z < -1.68) = 1 - P(Z 1.68)

= 1 - 0.95352 = 0.04648

P(Xbar $\leq$ 2.50) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{2.50-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z $\leq$ -3.92) = 1 - P(Z < 3.92)