The volume of the solid objects are 612π in³ and 1566πcm³
<h3>Volume of solid object</h3>
The given objects are composite figures consisting of two shapes.
The volume of the blue figure is expressed as;
Volume = Volume of cylinder + volume of hemisphere
Volume = πr²h + 2/3πr³
Volume = πr²(h + 2/3r)
Volume = π(6)²(13+2/3(6))
Volume = 36π(13 + 4)
Volume = 612π in³
For the other object
Volume = Volume of cylinder + volume of cone
Volume = πr²h + 1/3πr²h
Volume = π(9)²(15) + 1/3π(9)²(13)
Volume= 81π (15+13/3)
Volume= 1566πcm³
Hence the volume of the solid objects are 612π in³ and 1566πcm³
Learn more on volume of composite figures here: brainly.com/question/1205683
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Answer: 15
Step-by-step explanation:
If two points are together, then you subtract the numbers to get the distance
19 - 4 = 15
The answer would be 39/40.
1. Find the LCD of both of the fractions (LCD = 40)
2. Make the denominators the same as LCD (The LCD would be 40)
3. Simplify (24/40 + 15/40)
4. Join the denominators (24 + 15/40)
5. Simplify (39/40)
In decimal form its 0.975.
Answer: 40.8cm
Step-by-step explanation:
A hexagon is a polygon that is made up of 6 sides. The perimeter of a regular hexagon is calculated by multiplying the side given by 6
Since the length of a side of a regular hexagon is 6.8 cm, the perimeter will be:
= 6 × 6.8
= 40.8cm
If 12 balls fit in 2 boxes, 6 balls fit in 1 box. 78 / 6 = 13. 78 balls fit in 13 boxes. x = 13.
