Question

Using the formula do you sound level and disciples are use the intensity of the sound you're measuring. Set an alarm to normal conversation has an intensity of 3.2×10 to the -6

Answer 1

Answer:

65.1 decibels

Step-by-step explanation:

Given

$I = 3.2 * 10^{-6}$ --- intensity

Required

Determine the sound level

This is calculated using:

$B = 10\log(\frac{I}{I_o})$

Where:

$I_o = 1 * 10^{-12}$

So, we have:

$B = 10\log(\frac{3.2 * 10^{-6}}{1 * 10^{-12}})$

Apply law of indices

$B = 10\log(\frac{3.2 * 10^{-6+12}}{1})$

$B = 10\log(3.2 * 10^{6})$

Using a calculator, we have:

$B = 10*6.51$

$B = 65.1$