There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n
=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
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Answer:
12x + 96 ≥ 200
Step-by-step explanation:
Each ticket costs 12 each= 12x
He has already sold 96=+96
he needs to make 200
12x+96>= 200
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He made 12*40=480 dollars in total. 0.0765*480=36.72 dollars were withheld.
Answer:
2.86
Step-by-step explanation:
Add all of them together to get 20, divide by the total employees so 7, you get 2.857. Round to nearest hundredth to get 2.86