For number 5: 180 -139 = x
For number 6: x = 41
For number 7: x + 18 = 90 (not 100% sure)
For number 8: x = 72
For number 9: you could write an equation about an acute angle and divide it into 2 parts the have one side 3 + 8 and have the other x. Then you could go from there. I’m sorry if you can’t figure out number 9. I tried to think of something.
Answer:
14 you welcome
Step-by-step explanation:
Answer:
The answer is option 3.
Step-by-step explanation:
You have to substitute H+=2×10^(-9) into the equation of pH :
pH = -log[H+]
H+ = 2×10^(-9)
pH = -log[2×10^-9]
= 8.70 (3s.f)
Terms- 350n, 30n, 350, and (50+10n) (four terms)
coefficients- 350,30,and 10