Question

You open a savings account and deposit $1,000. After 1 year of earning continuously compounded interest.

Answer 1

Answer:

Step-by-step explanation:

$1036.66=1000e^{2r}\\ \\ r=(ln(1.03666))/2\\ \\ r=0.018\\ \\ b(x)=1000e^{(0.018x)}\\ \\ b(10)=1000e^{0.18}=\ 1197.22$