Answer: Choice B) y = (x+4)^2 - 1
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Reasoning:
The vertex is (h,k) = (-4,-1) so h = -4 and k = -1
In each answer choice, a = 1.
Plug a = 1, h = -4 and k = -1 into the equation below and simplify
y = a(x-h)^2 + k
y = 1(x-(-4))^2 + (-1)
y = (x+4)^2 - 1
A(n) = 2 + 9(n - 1) = 2 + 9n - 9
A(n + 1) = 2 + 9(n + 1 - 1) = 2 + 9n = (2 + 9n - 9) + 9 = A(n) + 9
Therefore, the recursive formular is A(n) = A(n - 1) + 9
The nut lands first on gorund
<em><u>Solution:</u></em>
The squirrel climbs down the tree in 2 seconds
Given that,
A squirrel is 24 feet up in a tree and tosses a nut out of the tree with an initial velocity of 8 feet per second
<em><u>The nuts height, h, at time t seconds can be represented by the equation:</u></em>


time cannot be negative, so ignore t = -1
Thus the nut takes 1.5 seconds to reach ground
From given,
The squirrel climbs down the tree in 2 seconds
Therefore, the nut lands first on gorund
The <u>possible rational zeros</u> of <u>polynomial function</u>
could be only among the <u>divisors</u> of the <u>free term</u> of this polynomial function.
The free term is 20 and the divisors of 20 are:

Answer: correct choice is C