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3 years ago

A fruit basket is filled with 8 bananas, 3 oranges, 5 apples, and 6 kiwis.

Mathematics

1 answer:

Reika [66]3 years ago

7 0

Answer:bananas

Step-by-step explanation:

Because 3+3 is 6 and 4+4 is 8

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Solve for h. 0.8h − 11.49 = 5.67 + 12.9 − 15.9h

Helga [31]

So the right answer is 1.8

Look at the attached picture

Hope it will help you

Good luck on your assignment

3 0

3 years ago

Someone who knows math more than I do, can you please answer this question for me, I'd appreciate it so much <3

Nonamiya [84]

Using the Pythagorean theorem, the other leg measures:
x = sqrt(35^2 - 32.6^2) = 12.74 cm
Since this is a right triangle, the base and height are simply the two sides that are perpendicular to each other.
Then the approximate area is (1/2)(leg 1)(leg 2) = (1/2)(32.6)(12.74) = 207.6 cm^2.

3 0

3 years ago

Weekly wages at a certain factory are

Naya [18.7K]

Answer:

Step-by-step explanation:

Weekly wages at a certain factory are

normally distributed. The formula for normal distribution is expressed as

z= (x - u)/s

Where

u = mean

s = standard deviation

x = weekly wages

From the given information,

u = 400

s = 50

The probability that a worker

selected at random makes between

$350 and $400 is expressed as

P(350 lesser than or equal to x lesser than or equal to 400)

For x = 350

z = (350 - 400)/50 = -50/50 = -1

z = -1

From the normal distribution table, the corresponding z score is 0.1587

For x = 400

z = (400 - 400)/50 = 0/50 = 0

z = 0

From the normal distribution table, the corresponding z score is 0.5

P(350 lesser than or equal to x lesser than or equal to 400)

= 0.5 - 0.1587 = 0.3413

4 0

3 years ago

Read 2 more answers

The gas tank on the back of a tanker truck can be equated to a cylinder with a diameter of 8 feet and a length of 19 feet. A gal

Leokris [45]

9514 1404 393

Answer:

driver's tank: 30,427 lb
farmer's tank: 12,811 lb

Step-by-step explanation:

The formula for the volume of a cylinder is ...

V = πr^2·h . . . radius r, height h

The radius of the driver's tank is half its diameter, so is (8 ft)/2 = 4 ft. Then the volume of that tank is ...

V = π(4 ft)^2·(19 ft) = 304π ft^3

Each cubic foot of gasoline has a mass of ...

(1728 in^3/ft^3)(0.0262 lb/in^3) = 45.2736 lb/ft^3

Then the total mass in the driver's full tank is ...

(304π ft^3)(45.2736 lb/ft^3) ≈ 43,238.3 lb

The farmer's tank is a scaled-down version of the driver's tank. It's volume will be scaled by the cube of the linear scale factor, so will be (2/3)^3 = 8/27 of the volume of the driver's tank.

The farmer's tank will hold a mass of (43,238.3 lb)(8/27) ≈ 12,811 lb.

The amount remaining in the driver's tank is 43,238 -12,811 = 30,427 lb.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Ctext%7Bquestion%7D%7D%7D%20%3A%20" id="TexFormula1"

Inga [223]

Answer:

$y=-\sqrt{3}x+2$

Step-by-step explanation:

We want to find the equation of a straight line that cuts off an intercept of 2 from the y-axis, and whose perpendicular distance from the origin is 1.

We will let Point M be (x, y). As we know, Point R will be (0, 2) and Point O (the origin) will be (0, 0).

First, we can use the distance formula to determine values for M. The distance formula is given by:

$\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Since we know that the distance between O and M is 1, d=1.

And we will let M(x, y) be (x₂, y₂) and O(0, 0) be (x₁, y₁). So:

$\displaystyle 1=\sqrt{(x-0)^2+(y-0)^2}$

Simplify:

$1=\sqrt{x^2+y^2}$

We can solve for y. Square both sides:

$1=x^2+y^2$

Rearranging gives:

$y^2=1-x^2$

Take the square root of both sides. Since M is in the first quadrant, we only need to worry about the positive case. Therefore:

$y=\sqrt{1-x^2}$

So, Point M is now given by (we substitute the above equation for y):

$M(x,\sqrt{1-x^2})$

We know that Segment OM is perpendicular to Line RM.

Therefore, their slopes will be negative reciprocals of each other.

So, let’s find the slope of each segment/line. We will use the slope formula given by:

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Segment OM:

For OM, we have two points: O(0, 0) and M(x, √(1-x²)). So, the slope will be:

$\displaystyle m_{OM}=\frac{\sqrt{1-x^2}-0}{x-0}=\frac{\sqrt{1-x^2}}{x}$

Line RM:

For RM, we have the two points R(0, 2) and M(x, √(1-x²)). So, the slope will be:

$\displaystyle m_{RM}=\frac{\sqrt{1-x^2}-2}{x-0}=\frac{\sqrt{1-x^2}-2}{x}$

Since their slopes are negative reciprocals of each other, this means that:

$m_{OM}=-(m_{RM})^{-1}$

Substitute:

$\displaystyle \frac{\sqrt{1-x^2}}{x}=-\Big(\frac{\sqrt{1-x^2}-2}{x}\Big)^{-1}$

Now, we can solve for x. Simplify:

$\displaystyle \frac{\sqrt{1-x^2}}{x}=\frac{x}{2-\sqrt{1-x^2}}$

Cross-multiply:

$x(x)=\sqrt{1-x^2}(2-\sqrt{1-x^2})$

Distribute:

$x^2=2\sqrt{1-x^2}-(\sqrt{1-x^2})^2$

Simplify:

$x^2=2\sqrt{1-x^2}-(1-x^2)$

Distribute:

$x^2=2\sqrt{1-x^2}-1+x^2$

So:

$0=2\sqrt{1-x^2}-1$

Adding 1 and then dividing by 2 yields:

$\displaystyle \frac{1}{2}=\sqrt{1-x^2}$

Then:

$\displaystyle \frac{1}{4}=1-x^2$

Therefore, the value of x is:

$\displaystyle \begin{aligned}\frac{1}{4}-1&=-x^2\\-\frac{3}{4}&=-x^2\\ \frac{3}{4}&=x^2\\ \frac{\sqrt{3}}{2}&=x\end{aligned}$

Then, Point M will be:

$\begin{aligned} \displaystyle M(x,\sqrt{1-x^2})&=M(\frac{\sqrt{3}}{2}, \sqrt{1-\Big(\frac{\sqrt{3}}{2}\Big)^2)}\\M&=(\frac{\sqrt3}{2},\frac{1}{2})\end{aligned}$

Therefore, the slope of Line RM will be:

$\displaystyle \begin{aligned}m_{RM}&=\frac{\frac{1}{2}-2}{\frac{\sqrt{3}}{2}-0} \\ &=\frac{\frac{-3}{2}}{\frac{\sqrt{3}}{2}}\\&=-\frac{3}{\sqrt3}\\&=-\sqrt3\end{aligned}$

And since we know that R is (0, 2), R is the y-intercept of RM. Then, using the slope-intercept form:

$y=mx+b$

We can see that the equation of Line RM is:

$y=-\sqrt{3}x+2$

6 0

3 years ago

Read 2 more answers