Answer:
discrete, the class boundaries are;
16 - 25
26 - 35
36 - 45
46 - 55
56 - 65
66 = 75
continuous, the class boundaries are;
16 to less than 26
26 to less than 36
36 to less than 46
46 to less than 56
56 to less than 66
66 to less than 76
Step-by-step explanation:
Given that;
Range of the dataset = maximum value - minimum value = 74 - 16 = 58
total number of data set n = 50
Rule : ≥ n
substitute value of n
≥ 50
k × log(2) = log( 50 )
k × 0.3010 = 1.69897
k = 1.69897 / 0.3010
k = 5.64
Hence, we have a total of 6 number of classes needed to be constructed.
so,
class width = 74 - 16 / 6 = 58 / 6 = 9.67
If the Data is discrete, the class boundaries are;
16 - 25
26 - 35
36 - 45
46 - 55
56 - 65
66 = 75
If the Data is continuous, the class boundaries are;
16 to less than 26
26 to less than 36
36 to less than 46
46 to less than 56
56 to less than 66
66 to less than 76
It took Mason 9.4 - 2.65 = 6.75 minutes to complete the Second Challenge.
Because the equation does not have any variable other than the x for the exponent.
The domain would be all real numbers even ones less than 1/2
so the answer is False
A quadrilateral is a 4 sided shape. Examples could include squares, trapezoids, rectangles, and rhombus.
Ok so when you distribute you get -60-12p+4p-20 then you will do -60+-20 which is -80 then you do -12p+4p which you get -8p then overall its -8p-80